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大数乘法与快速傅里叶变换

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 楼主| 发表于 2020-12-25 01:04 | 显示全部楼层
改造后的代码及运行结果:
Private Sub Command1_Click()
Dim x_() As Double, a As String
a = Trim(Text1)
ReDim x_(1 To Len(a))
For i1 = 1 To Len(a)
x_(i1) = Mid(a, i1, 1)
  Next
Dim n As Integer, i As Long, j As Long, mn As Long, lh As Long, t As Double, k As Long
'位序倒置
n = Len(a) '求数组大小,其值必须是2的幂
lh = n / 2
j = n / 2
For i = 1 To n - 2
If i < j Then '倒序
t = x_(j)
x_(j) = x_(i)
x_(i) = t
End If

Debug.Print i, j
k = lh '下面是向右进位算法
Do
If k > j Then Exit Do '高位是1吗
j = j - k '是的,高位置0
k = k / 2 '准备次高位的权
Loop Until k = 0 '次高位的权若非0,则检查新的次高位
j = j + k '非则若最高位是0,则置1
Text2 = Text2 & "  " & j
Next
End Sub

Private Sub Command2_Click()
Text1 = ""
Text2 = ""
End Sub
运行结果:
Text1=1234567812345678
Text2=  4  12  2  10  6  14  1  9  5  13  3  11  7  15.
Text1=12345678,
Text2= 2  6  1  5  3  7
这个不知道对不对,好像结果正确?
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 楼主| 发表于 2020-12-25 18:00 | 显示全部楼层
Text1=12345678,
Text2= 2  6  1  5  3  7

这个结果也有问题,缺少0  4 两位,哪去了?
应该是0  4  2  6  1  5  3  
Text1=1234567812345678
Text2=  4  12  2  10  6  14  1  9  5  13  3  11  7  15.
这个结果前面缺少了0  8 两位。
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 楼主| 发表于 2020-12-27 12:19 | 显示全部楼层
上传一下vb6.0文件,欢迎探讨,欢迎指导!

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 楼主| 发表于 2020-12-27 12:19 | 显示全部楼层
Private Sub Command1_Click()
Dim xr() As Double, a As String
a = Trim(Text1)
ReDim xr(0 To Len(a) - 1)
For i1 = 0 To Len(a) - 1
xr(i1) = Mid(a, i1 + 1, 1)
  Next
Dim l As Long, le As Long, le1 As Long, n As Long, r As Long, p As Long, q As Long, m As Byte
Dim wr As Double, w1 As Double, wlr As Double, wl1 As Double, tr As Double, t1 As Double
Dim pi As Double, t As Double
Dim xi()
n = Len(a) '求数组大小,其值必须是2的幂
m = 0
l = 2
pi = 3.14159265358979
Do
l = l + l
m = m + 1
Loop Until l > n
n = l / 2
ReDim xi(n - 1)

l = 1
Do
  le = 2 ^ l
  le1 = le / 2
  wr = 1
  wi = 0
  If l = 1 Then
  t = 0
  Else
  t = pi / 2 / le1
  End If
  w1r = Cos(t)
  w1i = -Sin(t)
  Print l
  r = 0
Do
  p = r
  Do
   q = p + le1
   
   tr = xr(q) * wr - xi(q) * wi
   ti = xr(q) * wi + xi(q) * wr
   
   xr(q) = xr(p) - tr
   xi(q) = xi(p) - ti
   xr(p) = xr(p) + tr
   xi(p) = xi(p) + ti
   Print p, q
   If l = m Then
   Print xr(p), xr(q)
   Else
   l = l
   End If
   
   p = p + le
Loop Until p > n - 2

wr = wr * w1r - wi * w1i
wi = wr * w1i + wi * w1r
r = r + 1
Loop Until r > le1 - 1
l = l + 1
Loop Until l > m

For i = 0 To n - 1 '仅输出模
   xr(i) = Sqr(xr(i) ^ 2 + xi(i) ^ 2)
   Text2 = Text2 & "  " & xr(i) & "+" & xi(i) & "i"
   Print xr(i)
   Next

End Sub

Private Sub Command2_Click()
Text1 = ""
Text2 = ""
End Sub

输入:Text1 =00070608,结果:
     21+0i  18.2402209235991+11.3168384736048i  8.52184907200135+1.2030095742831i  5.34099187879733+-4.98597437879115i  
7+0i  6.1679918952893+-4.31683847360479i  5.69207054900005+-1.2030095742831i  8.23483506410346+-2.01402562120885i
与正确值比较:12.9+10.9i, 2+7i, 3.1-1.1i, 7, 3.1+1.1i, 2-7i, 12.9-10.9i, 21也是不对。
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 楼主| 发表于 2020-12-27 12:27 | 显示全部楼层
输入:Text1 =80607000,结果:
      21+0i  19.494377694709+-5.47487373415292i  8.19257542063347+-4.21053350999086i  7.09407612810709+-2.05099623825891i  
7+0i  5.79930793819311+-0.525126265847085i  5.18613994716601+4.21053350999086i  8.08344810720862+8.05099623825891i
与正确值比较:12.9+10.9i, 2+7i, 3.1-1.1i, 7, 3.1+1.1i, 2-7i, 12.9-10.9i, 21也是不对。
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 楼主| 发表于 2020-12-27 18:49 | 显示全部楼层
这个VB6.0软件咋无法打开?
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 楼主| 发表于 2020-12-28 22:25 | 显示全部楼层
Private Sub Command1_Click()
Dim xr() As Double, a As String
a = Trim(Text1)
ReDim xr(0 To Len(a) - 1)
For i1 = 0 To Len(a) - 1
xr(i1) = Mid(a, i1 + 1, 1)
  Next
Dim l As Long, le As Long, le1 As Long, n As Long, r As Long, p As Long, q As Long, m As Byte
Dim wr As Double, w1 As Double, wlr As Double, wl1 As Double, tr As Double, t1 As Double
Dim pi As Double, t As Double
Dim xi()
n = Len(a) '求数组大小,其值必须是2的幂
m = 0
l = 2
pi = 3.14159265358979
Do
l = l + l
m = m + 1
Loop Until l > n
n = l / 2
ReDim xi(n - 1)

l = 1
Do
  le = 2 ^ l
  le1 = le / 2
  wr = 1
  wi = 0
  If l = 1 Then
  t = 0
  Else
  t = pi / le1
  End If
  w1r = Cos(t)
  w1i = -Sin(t)
  Print l
  r = 0
Do
  p = r
  Do
   q = p + le1
   
   tr = xr(q) * wr - xi(q) * wi
   ti = xr(q) * wi + xi(q) * wr
   
   xr(q) = xr(p) - tr
   xi(q) = xi(p) - ti
   xr(p) = xr(p) + tr
   xi(p) = xi(p) + ti
   Print p, q
   
   Print xr(p), xr(q)
   
   
   p = p + le
Loop Until p > n - 2

wr = wr * w1r - wi * w1i
wi = wr * w1i + wi * w1r
r = r + 1
Loop Until r > le1 - 1
l = l + 1
Loop Until l > m

For i = 0 To n - 1 '仅输出模
   xr(i) = Sqr(xr(i) ^ 2 + xi(i) ^ 2)
   Text2 = Text2 & "  " & xr(i) & "+" & xi(i) & "i"
   Next

End Sub

Private Sub Command2_Click()
Text1 = ""
Text2 = ""
End Sub

输入:Text1 =80607000,结果:
    21+0i  13.4143937430245+-3.50000000000001i  4.40338197130883+-3.19974746830584i  6.56830852046515+-1.17525253169417i  
7+0i  4.64263292831844+3.49999999999999i  3.3449607857897+3.19974746830584i  9.60982505463419+1.17525253169419i
与正确值比较:12.9+10.9i, 2+7i, 3.1-1.1i, 7, 3.1+1.1i, 2-7i, 12.9-10.9i, 21也是不对。
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 楼主| 发表于 2021-1-3 19:20 | 显示全部楼层
Private Sub Command1_Click()
Dim xr() As Double, a As String
a = Trim(Text1)
b = Trim(Text3)
ReDim xr(0 To Len(a) - 1): ReDim yr(0 To Len(b) - 1): ReDim zr(0 To Len(b) - 1)
For i1 = 0 To Len(a) - 1
xr(i1) = Mid(a, i1 + 1, 1)
yr(i1) = Mid(b, i1 + 1, 1)

  Next
Dim l As Long, le As Long, le1 As Long, n As Long, r As Long, p As Long, q As Long, m As Byte
Dim wr As Double, w1 As Double, wlr As Double, wl1 As Double, tr As Double, t1 As Double
Dim pi As Double, t As Double, tr1 As Double
Dim xi(): Dim yi(): Dim zi()
n = Len(a) '求数组大小,其值必须是2的幂
m = 0
l = 2
pi = 3.14159265358979
Do
l = l + l
m = m + 1
Loop Until l > n
n = l / 2
ReDim xi(n - 1): ReDim yi(n - 1): ReDim zi(n - 1)

l = 1
Do
  le = 2 ^ l
  le1 = le / 2
  wr = 1
  wi = 0
  t = pi / le1
  w1r = Cos(t)
  w1i = -Sin(t)
  r = 0
Do
  p = r
  Do
   q = p + le1
   
   tr = xr(q) * wr - xi(q) * wi
   ti = xr(q) * wi + xi(q) * wr
   
   tr1 = yr(q) * wr - yi(q) * wi
   ti1 = yr(q) * wi + yi(q) * wr
   
   xr(q) = xr(p) - tr
   xi(q) = xi(p) - ti
   xr(p) = xr(p) + tr
   xi(p) = xi(p) + ti
   
    yr(q) = yr(p) - tr1
   yi(q) = yi(p) - ti1
   yr(p) = yr(p) + tr1
   yi(p) = yi(p) + ti1
   
   p = p + le
Loop Until p > n - 1

wr = wr * w1r - wi * w1i
wi = wr * w1i + wi * w1r
r = r + 1
Loop Until r > le1 - 1
l = l + 1
Loop Until l > m

For i = 0 To n - 1 '仅输出模
   zr(i) = xr(i) * yr(i) - xi(i) * yi(i): zi(i) = xr(i) * yi(i) + xi(i) * yr(i)
   Text2 = Text2 & "  " & zr(i) & "+" & zi(i) & "i"
   Next
End Sub

Private Sub Command2_Click()
Text1 = ""
Text2 = ""
Text3 = ""
End Sub


输入:Text1 =80607000,Text2=20403000,结果:
189+0i  48.1200576850889+-33.8492424049177i  -9.10907287525383+0.845301243345486i  8.07394476689+-4.83093657874164i
  21+0i  -5.62005768508875+4.15075759508251i  -6.76592712474619+-6.46840725563929i  24.7688582392567+7.92894805108087i
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 楼主| 发表于 2021-1-4 11:15 | 显示全部楼层
Private Sub Command1_Click()
Dim xr() As Double, a As String
a = Trim(Text1)
b = Trim(Text3)
ReDim xr(0 To Len(a) - 1): ReDim yr(0 To Len(b) - 1): ReDim zr(0 To Len(b) - 1)
For i1 = 0 To Len(a) - 1
xr(i1) = Mid(a, i1 + 1, 1)
yr(i1) = Mid(b, i1 + 1, 1)

  Next
Dim l As Long, le As Long, le1 As Long, n As Long, r As Long, p As Long, q As Long, m As Byte
Dim wr As Double, w1 As Double, wlr As Double, wl1 As Double, tr As Double, t1 As Double
Dim pi As Double, t As Double, tr1 As Double
Dim xi(): Dim yi(): Dim zi()
n = Len(a) '求数组大小,其值必须是2的幂
m = 0
l = 2
pi = 3.14159265358979
Do
l = l + l
m = m + 1
Loop Until l > n
n = l / 2
ReDim xi(n - 1): ReDim yi(n - 1): ReDim zi(n - 1)

l = 1
Do
  le = 2 ^ l
  le1 = le / 2
  wr = 1
  wi = 0
  t = pi / le1
  w1r = Cos(t)
  w1i = -Sin(t)
  r = 0
Do
  p = r
  Do
   q = p + le1
   
   tr = xr(q) * wr - xi(q) * wi
   ti = xr(q) * wi + xi(q) * wr
   
   tr1 = yr(q) * wr - yi(q) * wi
   ti1 = yr(q) * wi + yi(q) * wr
   
   xr(q) = xr(p) - tr
   xi(q) = xi(p) - ti
   xr(p) = xr(p) + tr
   xi(p) = xi(p) + ti
   
    yr(q) = yr(p) - tr1
   yi(q) = yi(p) - ti1
   yr(p) = yr(p) + tr1
   yi(p) = yi(p) + ti1
   
   p = p + le
Loop Until p > n - 1

wr = wr * w1r - wi * w1i
wi = wr * w1i + wi * w1r
r = r + 1
Loop Until r > le1 - 1
l = l + 1
Loop Until l > m

For i = 0 To n - 1 '仅输出模
   zr(i) = xr(i) * yr(i) - xi(i) * yi(i): zi(i) = xr(i) * yi(i) + xi(i) * yr(i)
   If InStr(zr(i), ".") = 0 Then
   zr(i) = zr(i)
   Else
   a1 = Left(zr(i), InStr(zr(i), ".") - 1)
   b1 = Mid(zr(i), InStr(zr(i), "."), 3)
   zr(i) = a1 & b1
   End If
   If InStr(zi(i), ".") = 0 Then
   zi(i) = zi(i)
   Else
   a2 = Left(zi(i), InStr(zi(i), ".") - 1)
   b2 = Mid(zi(i), InStr(zi(i), "."), 3)
   zi(i) = a2 & b2
   End If
   s = zr(i) & "/" & s
   s1 = zi(i) & "/" & s1
   Next
   Text2 = s1
End Sub

Private Sub Command2_Click()
Text1 = ""
Text2 = ""
Text3 = ""
End Sub

输入:Text1 =80607000,Text2=20403000,结果:
24.76/-6.76/-5.62/21/8.07/-9.10/48.12/189/
  7.92/-6.46/4.15/0/-4.83/0.84/-33.84/0/
与正确值比较:-13.6+123.4i, -25-8i, -2.4-5.8i, 21, -2.4+5.8i, -25+8i, -13.6-123.4i, 189也是不对。
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 楼主| 发表于 2021-1-6 23:09 | 显示全部楼层
Private Sub Command1_Click()
Dim xr() As Double, a As String
a = Trim(Text1)
b = Trim(Text3)
ReDim xr(0 To Len(a) - 1): ReDim yr(0 To Len(b) - 1): ReDim zr(0 To Len(b) - 1)
For i1 = 0 To Len(a) - 1
xr(i1) = Mid(a, i1 + 1, 1)
yr(i1) = Mid(b, i1 + 1, 1)

  Next
Dim l As Long, le As Long, le1 As Long, n As Long, r As Long, p As Long, q As Long, m As Byte
Dim wr As Double, w1 As Double, wlr As Double, wl1 As Double, tr As Double, t1 As Double
Dim pi As Double, t As Double, tr1 As Double
Dim xi(): Dim yi(): Dim zi()
n = Len(a) '求数组大小,其值必须是2的幂
m = 0
l = 2
pi = 3.14159265358979
Do
l = l + l
m = m + 1
Loop Until l > n
n = l / 2
ReDim xi(n - 1): ReDim yi(n - 1): ReDim zi(n - 1)

l = 1
Do
  le = 2 ^ l
  le1 = le / 2
  wr = 1
  wi = 0
  t = pi / le1
  w1r = Cos(t)
  w1i = -Sin(t)
  r = 0
Do
  p = r
  Do
   q = p + le1
   
   tr = xr(q) * wr - xi(q) * wi
   ti = xr(q) * wi + xi(q) * wr
   
   tr1 = yr(q) * wr - yi(q) * wi
   ti1 = yr(q) * wi + yi(q) * wr
   
   xr(q) = xr(p) - tr
   xi(q) = xi(p) - ti
   xr(p) = xr(p) + tr
   xi(p) = xi(p) + ti
   
    yr(q) = yr(p) - tr1
   yi(q) = yi(p) - ti1
   yr(p) = yr(p) + tr1
   yi(p) = yi(p) + ti1
   
   p = p + le
Loop Until p > n - 1

wr = wr * w1r - wi * w1i
wi = wr * w1i + wi * w1r
r = r + 1
Loop Until r > le1 - 1
l = l + 1
Loop Until l > m

For i = 0 To n - 1 '仅输出模
   zr(i) = xr(i) * yr(i) - xi(i) * yi(i): zi(i) = xr(i) * yi(i) + xi(i) * yr(i)
   If InStr(zr(i), ".") = 0 Then
   zr(i) = zr(i)
   Else
   a1 = Left(zr(i), InStr(zr(i), ".") - 1)
   b1 = Mid(zr(i), InStr(zr(i), "."), 3)
   zr(i) = a1 & b1
   End If
   If InStr(zi(i), ".") = 0 Then
   zi(i) = zi(i)
   Else
   a2 = Left(zi(i), InStr(zi(i), ".") - 1)
   b2 = Mid(zi(i), InStr(zi(i), "."), 3)
   zi(i) = a2 & b2
   End If
   s = "/" & zr(i) & s
   s1 = "/" & zi(i) & s1
   Next
  s2 = nifft(Trim(s), Trim(s1))
   Text2 = s2
End Sub

Private Sub Command2_Click()
Text1 = ""
Text2 = ""
Text3 = ""
End Sub

Private Function nifft(sa As String, sb As String) As String
Dim l As Long, le As Long, le1 As Long, j As Long, r As Long, p As Long, q As Long, m As Byte
Dim wr As Double, w1 As Double, wlr As Double, wl1 As Double, tr As Double, t1 As Double
Dim pi As Double, t As Double, tr1 As Double
Dim xi(): Dim yi(): Dim zi()
Dim xr(), yr(), zr()
s2 = Split(sa, "/")
s3 = Split(sb, "/")
   j = UBound(s2)
   n = j
  For k = 1 To j
      n1 = n1 + 1
       ReDim Preserve xr(0 To n1 - 1)
       ReDim Preserve yr(0 To n1 - 1)
      xr(n1 - 1) = s2(n1): yr(n1 - 1) = s3(n1)
    Next
   

ReDim zr(0 To j - 1)

m = 0
l = 2
pi = 3.14159265358979
Do
l = l + l
m = m + 1
Loop Until l > n
n = l / 2
ReDim xi(n - 1): ReDim yi(n - 1): ReDim zi(n - 1)

l = 1
Do
  le = 2 ^ l
  le1 = le / 2
  wr = 1
  wi = 0
  t = pi / le1
  w1r = Cos(t)
  w1i = -Sin(t)
  r = 0
Do
  p = r
  Do
   q = p + le1
   
   tr = xr(q) * wr - xi(q) * wi
   ti = xr(q) * wi + xi(q) * wr
   
   tr1 = yr(q) * wr - yi(q) * wi
   ti1 = yr(q) * wi + yi(q) * wr
   
   xr(q) = xr(p) - tr
   xi(q) = xi(p) - ti
   xr(p) = xr(p) + tr
   xi(p) = xi(p) + ti
   
    yr(q) = yr(p) - tr1
   yi(q) = yi(p) - ti1
   yr(p) = yr(p) + tr1
   yi(p) = yi(p) + ti1
   
   p = p + le
Loop Until p > n - 1

wr = wr * w1r - wi * w1i
wi = wr * w1i + wi * w1r
r = r + 1
Loop Until r > le1 - 1
l = l + 1
Loop Until l > m

For i = 0 To n - 1 '仅输出模
zr(i) = xr(i) + yr(i) + xi(i) + yi(i)
   If InStr(zr(i), ".") = 0 Then
   zr(i) = zr(i)
   Else
   a1 = Left(zr(i), InStr(zr(i), ".") - 1)
   b1 = Mid(zr(i), InStr(zr(i), "."), 3)
   zr(i) = a1 & b1
   End If
   
   s1 = Int(Val(zr(i) + 0.5))
   s = "/" & s1 & s
   Next
   
   
nifft = s

End Function


输入:Text1 =80607000,Text2=20403000,结果:
/50/-65/44/-159/41/65/48/237
与正确值比较:0, 0, 0, 24, 46, 65, 38, 16也是不对。
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