今天2022.09.10教师节，计算一下从20220910开始的连续50个偶数的素对数量

愚工688 · 发表于 2022-9-10 11:42

先筛选出素对数量的真值，后面再用计算式计算，看看相对误差会怎么样：

20220910:50:2

G(20220910) = 74971
G(20220912) = 107240
G(20220914) = 64869
G(20220916) = 53915
G(20220918) = 107235
G(20220920) = 71576
G(20220922) = 58479
G(20220924) = 106943
G(20220926) = 59967
G(20220928) = 72746
G(20220930) = 143344
G(20220932) = 53883
G(20220934) = 53737
G(20220936) = 107895
G(20220938) = 53436
G(20220940) = 76734
G(20220942) = 130533
G(20220944) = 55258
G(20220946) = 55706
G(20220948) = 119372
G(20220950) = 71632
G(20220952) = 54343
G(20220954) = 120050
G(20220956) = 71844
G(20220958) = 54777
G(20220960) = 144878
G(20220962) = 53722
G(20220964) = 53566
G(20220966) = 107602
G(20220968) = 53652
G(20220970) = 95441
G(20220972) = 108034
G(20220974) = 53997
G(20220976) = 53839
G(20220978) = 114973
G(20220980) = 78076
G(20220982) = 53616
G(20220984) = 131596
G(20220986) = 53894
G(20220988) = 53684
G(20220990) = 158123
G(20220992) = 59582
G(20220994) = 53763
G(20220996) = 107722
G(20220998) = 66705
G(20221000) = 72767
G(20221002) = 114525
G(20221004) = 55524
G(20221006) = 58572
G(20221008) = 112078

count = 50, algorithm = 2, working threads = 2, time use 0.046 sec

愚工688 · 发表于 2022-9-10 12:59

本帖最后由愚工688 于 2022-9-10 08:03 编辑

先用连乘式计算前面31个连续偶数的下界计算值:
可以看到，区域素对下界计算值,infS(m)是随着偶数增大而缓慢的近乎线性增大的 .[ infS(m)=inf(m)/k(m) ]

G(20220910) = 74971； inf( 20220910 )≈  73932.7 , Δ≈-0.01385 ,infS(m) = 52929.09 , k(m)= 1.39683
G(20220912) = 107240； inf( 20220912 )≈  105858.2 , Δ≈-0.01289 ,infS(m) = 52929.09 , k(m)= 2
G(20220914) = 64869； inf( 20220914 )≈  63873.8 , Δ≈-0.01534 ,infS(m) = 52929.10 , k(m)= 1.20678
G(20220916) = 53915； inf( 20220916 )≈  53117.5 , Δ≈-0.01479 ,infS(m) = 52929.10 , k(m)= 1.00356
G(20220918) = 107235； inf( 20220918 )≈  105858.2 , Δ≈-0.01284 ,infS(m) = 52929.11 , k(m)= 2
G(20220920) = 71576； inf( 20220920 )≈  70572.2 , Δ≈-0.01403 ,infS(m) = 52929.11 , k(m)= 1.33333
G(20220922) = 58479； inf( 20220922 )≈  57834.7 , Δ≈-0.01102 ,infS(m) = 52929.12 , k(m)= 1.09268
G(20220924) = 106943； inf( 20220924 )≈  105858.3 , Δ≈-0.01015 ,infS(m) = 52929.12 , k(m)= 2
G(20220926) = 59967； inf( 20220926 )≈  59245.8 , Δ≈-0.01203 ,infS(m) = 52929.13 , k(m)= 1.11934
G(20220928) = 72746；  inf( 20220928 )≈  71678.3 , Δ≈-0.01468 ,infS(m) = 52929.13 , k(m)= 1.35423
G(20220930) = 143344； inf( 20220930 )≈  141144.4 , Δ≈-0.01535 ,infS(m) = 52929.14 , k(m)= 2.66667
G(20220932) = 53883； inf( 20220932 )≈  53238.7 , Δ≈-0.0096 ,infS(m) = 52929.14 , k(m)= 1.00585
G(20220934) = 53737； inf( 20220934 )≈  52929.2 , Δ≈-0.01504 ,infS(m) = 52929.15 , k(m)= 1
G(20220936) = 107895； inf( 20220936 )≈  106286 , Δ≈-0.01491 ,infS(m) = 52929.16 , k(m)= 2.00808
G(20220938) = 53436； inf( 20220938 )≈  52929.2 , Δ≈-0.00948 ,infS(m) = 52929.16 , k(m)= 1
G(20220940) = 76734； inf( 20220940 )≈  75502 ,    Δ≈-0.01606 ,infS(m) = 52929.17 , k(m)= 1.42647
G(20220942) = 130533； inf( 20220942 )≈  128871 , Δ≈-0.01273 ,infS(m) = 52929.17 , k(m)= 2.43478
G(20220944) = 55258； inf( 20220944 )≈  54441.4 , Δ≈-0.01478 ,infS(m) = 52929.18 , k(m)= 1.02857
G(20220946) = 55706； inf( 20220946 )≈  54889.5 , Δ≈-0.01466 ,infS(m) = 52929.18 , k(m)= 1.03704
G(20220948) = 119372； inf( 20220948 )≈  117620.4 , Δ≈-0.01468 ,infS(m) = 52929.19 , k(m)= 2.22222
G(20220950) = 71632； inf( 20220950 )≈  70572.3 , Δ≈-0.01480 ,infS(m) = 52929.19 , k(m)= 1.33333
G(20220952) = 54343； inf( 20220952 )≈  53857.8 , Δ≈-0.00893 ,infS(m) = 52929.20 , k(m)= 1.01754
G(20220954) = 120050； inf( 20220954 )≈  118443 , Δ≈-0.01339 ,infS(m) = 52929.20 , k(m)= 2.23776
G(20220956) = 71844； inf( 20220956 )≈  71014 ,    Δ≈-0.01155 ,infS(m) = 52929.21 , k(m)= 1.34168
G(20220958) = 54777； inf( 20220958 )≈  53962.3 , Δ≈-0.01488 ,infS(m) = 52929.21 , k(m)= 1.01952
G(20220960) = 144878； inf( 20220960 )≈  142892.3 , Δ≈-0.01371 ,infS(m) = 52929.22 , k(m)= 2.69969
G(20220962) = 53722； inf( 20220962 )≈  52929.2 , Δ≈-0.01476 ,infS(m) = 52929.22 , k(m)= 1
G(20220964) = 53566； inf( 20220964 )≈  52929.2 , Δ≈-0.01189 ,infS(m) = 52929.23 , k(m)= 1
G(20220966) = 107602； inf( 20220966 )≈  106183.2 , Δ≈-0.01319 ,infS(m) = 52929.23 , k(m)= 2.00614
G(20220968) = 53652； inf( 20220968 )≈  53010.6 , Δ≈-0.01195 ,infS(m) = 52929.24 , k(m)= 1.00154
G(20220970) = 95441； inf( 20220970 )≈  94096.4 , Δ≈-0.01409 ,infS(m) = 52929.24 , k(m)= 1.77778
time start =11:48:17  ,time end =11:48:24 ,time use =
备注：使用修正系数的连乘式对亿以下偶数的素对下界的计算精度不是很高，除非把使用同一修正系数的偶数范围限制的更小。

愚工688 · 发表于 2022-9-10 13:36

再用对数计算式计算后面的30个偶数的素对数量：

  素对计算式：Xi(M)=t2*c1*M/(logM)^2  ；
  式中：t2=1.358-(log(M))^(.5)*0.05484； c1:只计算√M内素数的类似拉曼扭杨系数。

  G(20220970) = 95441    ;Xi(M)≈ 95037.06    δxi(M)≈?-0.004233；
  G(20220972) = 108034 ;Xi(M)≈ 107606.49 δxi(M)≈?-0.003957；
  G(20220974) = 53997    ;Xi(M)≈ 53714.14    δxi(M)≈?-0.005241；
  G(20220976) = 53839    ;Xi(M)≈ 53574.64    δxi(M)≈?-0.004911；
  G(20220978) = 114973 ;Xi(M)≈ 114564.69 δxi(M)≈?-0.003551；
  G(20220980) = 78076    ;Xi(M)≈ 77757.63    δxi(M)≈?-0.004078；
  G(20220982) = 53616    ;Xi(M)≈ 53458.38    δxi(M)≈?-0.002939；
  G(20220984) = 131596 ;Xi(M)≈ 130989.08 δxi(M)≈?-0.004613；
  G(20220986) = 53894    ;Xi(M)≈ 53542.04    δxi(M)≈?-0.006531；
  G(20220988) = 53684    ;Xi(M)≈ 53458.39    δxi(M)≈?-0.004202；
  G(20220990) = 158123 ;Xi(M)≈ 157426.04 δxi(M)≈?-0.004408；
  G(20220992) = 59582    ;Xi(M)≈ 59398.22    δxi(M)≈?-0.003085；
  G(20220994) = 53763    ;Xi(M)≈ 53458.41    δxi(M)≈?-0.005666；
  G(20220996) = 107722 ;Xi(M)≈ 107476.59 δxi(M)≈?-0.002287；
  G(20220998) = 66705    ;Xi(M)≈ 66598.94    δxi(M)≈?-0.001589；
  G(20221000) = 72767    ;Xi(M)≈ 72544.65    δxi(M)≈?-0.003055；
  G(20221002) = 114525 ;Xi(M)≈ 113731.33 δxi(M)≈?-0.006933；
  G(20221004) = 55524    ;Xi(M)≈ 55438.37    δxi(M)≈?-0.000731；
  G(20221006) = 58572    ;Xi(M)≈ 58318.29    δxi(M)≈?-0.004331；
  G(20221008) = 112078 ;Xi(M)≈ 111795.44 δxi(M)≈?-0.002521；
  time start =13:05:28, time end =13:05:31

可以看到，虽然使用了两个不同计算原理的计算式，都能够比较接近的计算出偶数能够分成的素对数量。

愚工688 · 发表于 2022-9-11 08:00

使用连乘式计算亿以上的偶数的素对，计算精度还是不错的。
计算教师节后加2个0的连续偶数的素对数量的下界计算值：
（可以看到，误差波动仅仅在万分位上）

inf( 2022091000 )≈  4456115.2 , jd ≈0.9936 ,infS(m) = 3190173.41 , k(m)= 1.39683
inf( 2022091002 )≈  6607515.9 , jd ≈0.9932 ,infS(m) = 3190173.41 , k(m)= 2.07121
inf( 2022091004 )≈  3310631.6 , jd ≈0.9938 ,infS(m) = 3190173.42 , k(m)= 1.03776
inf( 2022091006 )≈  3482738.8 , jd ≈0.9935 ,infS(m) = 3190173.42 , k(m)= 1.09171
inf( 2022091008 )≈  7656416.2 , jd ≈0.9938 ,infS(m) = 3190173.42 , k(m)= 2.4
inf( 2022091010 )≈  4537135.5 , jd ≈0.9938 ,infS(m) = 3190173.43 , k(m)= 1.42222
inf( 2022091012 )≈  3200301.0 , jd ≈0.9936 ,infS(m) = 3190173.43 , k(m)= 1.00317
inf( 2022091014 )≈  6390687.8 , jd ≈0.9936 ,infS(m) = 3190173.43 , k(m)= 2.00324
inf( 2022091016 )≈  3550451.0 , jd ≈0.9937 ,infS(m) = 3190173.44 , k(m)= 1.11293
inf( 2022091018 )≈  3190629.5 , jd ≈0.9933 ,infS(m) = 3190173.44 , k(m)= 1.00014
inf( 2022091020 )≈  8507129.2 , jd ≈0.9937 ,infS(m) = 3190173.44 , k(m)= 2.66667
inf( 2022091022 )≈  3834620.6 , jd ≈0.9938 ,infS(m) = 3190173.45 , k(m)= 1.20201
time start =07:09:22  ,time end =07:10:14 ,time use =

inf( 2022091000 ) = 1/(1+ .148 )*( 2022091000 /2 -2)*p(m) ≈ 4456115.2
inf( 2022091002 ) = 1/(1+ .148 )*( 2022091002 /2 -2)*p(m) ≈ 6607515.9
inf( 2022091004 ) = 1/(1+ .148 )*( 2022091004 /2 -2)*p(m) ≈ 3310631.6
inf( 2022091006 ) = 1/(1+ .148 )*( 2022091006 /2 -2)*p(m) ≈ 3482738.8
inf( 2022091008 ) = 1/(1+ .148 )*( 2022091008 /2 -2)*p(m) ≈ 7656416.2
inf( 2022091010 ) = 1/(1+ .148 )*( 2022091010 /2 -2)*p(m) ≈ 4537135.5
inf( 2022091012 ) = 1/(1+ .148 )*( 2022091012 /2 -2)*p(m) ≈ 3200301
inf( 2022091014 ) = 1/(1+ .148 )*( 2022091014 /2 -2)*p(m) ≈ 6390687.8
inf( 2022091016 ) = 1/(1+ .148 )*( 2022091016 /2 -2)*p(m) ≈ 3550451
inf( 2022091018 ) = 1/(1+ .148 )*( 2022091018 /2 -2)*p(m) ≈ 3190629.5
inf( 2022091020 ) = 1/(1+ .148 )*( 2022091020 /2 -2)*p(m) ≈ 8507129.2
inf( 2022091022 ) = 1/(1+ .148 )*( 2022091022 /2 -2)*p(m) ≈ 3834620.6

2022091000:12:2

G(2022091000) = 4484893
G(2022091002) = 6652588
G(2022091004) = 3331336
G(2022091006) = 3505572
G(2022091008) = 7704083
G(2022091010) = 4565322
G(2022091012) = 3220944
G(2022091014) = 6431713
G(2022091016) = 3572925
G(2022091018) = 3212103
G(2022091020) = 8561194
G(2022091022) = 3858656

愚工688 · 发表于 2022-9-11 08:30

本帖最后由愚工688 于 2022-9-11 00:36 编辑

即使是100年后的教师节加2个0的连续偶数的素对下界计算值的计算精度仍然不错：

inf( 2122091000 )≈  4782307.0 , jd ≈0.9945 ,infS(m) = 3334139.72 , k(m)= 1.43435
inf( 2122091002 )≈  3367817.9 , jd ≈0.9941 ,infS(m) = 3334139.73 , k(m)= 1.0101
inf( 2122091004 )≈  7416823.6 , jd ≈0.9942 ,infS(m) = 3334139.73 , k(m)= 2.22451
inf( 2122091006 )≈  4057148.2 , jd ≈0.9942 ,infS(m) = 3334139.73 , k(m)= 1.21685
inf( 2122091008 )≈  3487629.4 , jd ≈0.9939 ,infS(m) = 3334139.73 , k(m)= 1.04604
inf( 2122091010 )≈  9729140.0 , jd ≈0.9938 ,infS(m) = 3334139.74 , k(m)= 2.91804
inf( 2122091012 )≈  3336730.4 , jd ≈0.9943 ,infS(m) = 3334139.74 , k(m)= 1.00078
inf( 2122091014 )≈  3334420.3 , jd ≈0.9939 ,infS(m) = 3334139.74 , k(m)= 1.00008
inf( 2122091016 )≈  6668279.5 , jd ≈0.9942 ,infS(m) = 3334139.75 , k(m)= 2
inf( 2122091018 )≈  3334368.8 , jd ≈0.9938 ,infS(m) = 3334139.75 , k(m)= 1.00007
inf( 2122091020 )≈  5409941.5 , jd ≈0.9937 ,infS(m) = 3334139.75 , k(m)= 1.62259
inf( 2122091022 )≈  6851592.0 , jd ≈0.9942 ,infS(m) = 3334139.76 , k(m)= 2.05498
time start =08:12:14  ,time end =08:13:07 ,time use =

2122091000:12:2

G(2122091000) = 4808839
G(2122091002) = 3387697
G(2122091004) = 7460133
G(2122091006) = 4080707
G(2122091008) = 3509091
G(2122091010) = 9790167
G(2122091012) = 3355850
G(2122091014) = 3354879
G(2122091016) = 6707242
G(2122091018) = 3355204
G(2122091020) = 5444415
G(2122091022) = 6891716

count = 12, algorithm = 2, working threads = 2, time use 0.474 sec

计算式：
inf( 2122091000 ) = 1/(1+ .148 )*( 2122091000 /2 -2)*p(m) ≈ 4782307
inf( 2122091002 ) = 1/(1+ .148 )*( 2122091002 /2 -2)*p(m) ≈ 3367817.9
inf( 2122091004 ) = 1/(1+ .148 )*( 2122091004 /2 -2)*p(m) ≈ 7416823.6
inf( 2122091006 ) = 1/(1+ .148 )*( 2122091006 /2 -2)*p(m) ≈ 4057148.2
inf( 2122091008 ) = 1/(1+ .148 )*( 2122091008 /2 -2)*p(m) ≈ 3487629.4
inf( 2122091010 ) = 1/(1+ .148 )*( 2122091010 /2 -2)*p(m) ≈ 9729140
inf( 2122091012 ) = 1/(1+ .148 )*( 2122091012 /2 -2)*p(m) ≈ 3336730.4
inf( 2122091014 ) = 1/(1+ .148 )*( 2122091014 /2 -2)*p(m) ≈ 3334420.3
inf( 2122091016 ) = 1/(1+ .148 )*( 2122091016 /2 -2)*p(m) ≈ 6668279.5
inf( 2122091018 ) = 1/(1+ .148 )*( 2122091018 /2 -2)*p(m) ≈ 3334368.8
inf( 2122091020 ) = 1/(1+ .148 )*( 2122091020 /2 -2)*p(m) ≈ 5409941.5
inf( 2122091022 ) = 1/(1+ .148 )*( 2122091022 /2 -2)*p(m) ≈ 6851592

从这里可以看到，大偶数素对的计算采用连乘式修正系数计算的优越性——同一系数计算范围广阔，计算精度高。

愚工688 · 发表于 2022-9-11 14:11

本帖最后由愚工688 于 2022-9-11 06:14 编辑

愚工688 发表于 2022-9-11 00:30
即使是100年后的教师节加2个0的连续偶数的素对下界计算值的计算精度仍然不错：

答时空伴随者：

M —— 偶数，
K（m）——偶数M含有的奇素因子p构成的系数，K（m）=π[(P-1)/(P-2)]，素因子系数反应出偶数素对数量的波动幅度，没有奇数因子时，K（m）=1，
time use 0.474 sec——这是电脑运行程序的时间，一般不是太大的偶数的素数对，电脑几乎是即刻得出。

素因子系数K（m）反应出偶数素对数量的波动幅度，见例图：

愚工688 · 发表于 2022-9-11 16:15

为什么使用修正系数的连乘式对亿以下偶数的素对下界的计算精度不是很高呢？
主要原因是偶数比较小的区域内，各偶数的计算值的相对误差统计的标准偏差不是很小，说明其波动比较大。即使使用修正系数修正，也只能满足波谷部分偶数下界计算值的精度。
例：9万——10万的偶数的相对误差统计数据：
M=[ 90002 , 100000 ]  r= 313  n= 5000  μ= .0218  σχ= .0174  δ(min)=-.038  δ(max)= .112

而大偶数区域的偶数的相对误差统计数据就不是这样。
例：10亿—— 100亿的各个样本区域的相对误差的统计计算数据：
1000000000 - 1000000098 : n= 50 μ= .1368  σx= .0004  δ(min)= .1356  δ(max)= .138
2000000000 - 2000000098 : n= 50 μ= .1406  σx= .0003  δ(min)= .1399  δ(max)= .141
3000000000 - 3000000098 : n= 50 μ= .1431  σx= .0002  δ(min)= .1425  δ(max)= .1435
4000000000 - 4000000098 : n= 50 μ= .1449  σx= .0003  δ(min)= .1441  δ(max)= .1456
5000000000 - 5000000098 : n= 50 μ= .1462  σx= .0003  δ(min)= .1456  δ(max)= .1468
5999999990 - 6000000088 : n= 50 μ= .1471  σx= .0002  δ(min)= .1466  δ(max)= .1474
8000000000 - 8000000050 : n= 26 μ= .1486  σx= .0002  δ(min)= .1481  δ(max)= .1490
10000000000-10000000098 : n= 50 μ= .1494  σx= .0002  δ(min)= .1491  δ(max)= .1497

可以看到各个区域的相对误差的极大值与极小值都相差不多；即使是不同值区域的极值，也相差不多。因此就能够通过修正系数的介入，全面的提高计算值的计算精度。
我上面采用的 μ= .148的修正系数，至少可计算到60亿的偶数范围偶数素对的下界计算值，到80亿以上，则会正的相对误差，而不再是下界计算值了。当然计算值精度是比较高的。

时空伴随者 · 发表于 2022-9-11 18:13

count = 50, algorithm = 2, working threads = 2, time use 0.046 sec
很惊奇、非常惊奇、特别惊奇！这些数据在这么短的时间内就有了结果。
我的程序要用好几分钟才行。
2022-09-11 18:14:40
............................................................
G(20220910) = 74971
G(20220912) = 107240
G(20220914) = 64869
G(20220916) = 53915
G(20220918) = 107235
G(20220920) = 71576
G(20220922) = 58479
G(20220924) = 106943
G(20220926) = 59967
G(20220928) = 72746
G(20220930) = 143344
G(20220932) = 53883
G(20220934) = 53737
G(20220936) = 107895
G(20220938) = 53436
G(20220940) = 76734
G(20220942) = 130533
G(20220944) = 55258
G(20220946) = 55706
G(20220948) = 119372
G(20220950) = 71632
G(20220952) = 54343
G(20220954) = 120050
G(20220956) = 71844
G(20220958) = 54777
G(20220960) = 144878
G(20220962) = 53722
G(20220964) = 53566
G(20220966) = 107602
G(20220968) = 53652
G(20220970) = 95441
G(20220972) = 108034
G(20220974) = 53997
G(20220976) = 53839
G(20220978) = 114973
G(20220980) = 78076
G(20220982) = 53616
G(20220984) = 131596
G(20220986) = 53894
G(20220988) = 53684
G(20220990) = 158123
G(20220992) = 59582
G(20220994) = 53763
G(20220996) = 107722
G(20220998) = 66705
G(20221000) = 72767
G(20221002) = 114525
G(20221004) = 55524
G(20221006) = 58572
G(20221008) = 112078
G(20221010) = 71314
G(20221012) = 65582
G(20221014) = 119928
G(20221016) = 56785
G(20221018) = 55615
G(20221020) = 143379
G(20221022) = 53555
G(20221024) = 57196
G(20221026) = 130023
G(20221028) = 53828
用时 266.13946437835693 秒

愚工688 · 发表于 2022-9-21 17:12

时空伴随者发表于 2022-9-11 10:13
count = 50, algorithm = 2, working threads = 2, time use 0.046 sec
很惊奇、非常惊奇、特别惊奇！这些 ...

能够学会先进的编程方法就会带来不一样的体会！
这个素对筛选程序是网友深圳的黄博士赠予我的，使用C++语言编程的。对于万亿以下的连续偶数的素数对的计算，是比较快的。一般百亿级的连续偶数的素对数据，很随意就得到了。

20220921000:20:2

G(20220921000) = 87854784
G(20220921002) = 26918148
G(20220921004) = 25973417
G(20220921006) = 62828426
G(20220921008) = 25913440
G(20220921010) = 34556861
G(20220921012) = 51825765
G(20220921014) = 34384857
G(20220921016) = 25914755
G(20220921018) = 51836749
G(20220921020) = 34558306
G(20220921022) = 25963247
G(20220921024) = 51827967
G(20220921026) = 25912098
G(20220921028) = 34808694
G(20220921030) = 69179942
G(20220921032) = 28268312
G(20220921034) = 25914938
G(20220921036) = 54198248
G(20220921038) = 27431260

count = 20, algorithm = 2, working threads = 2, time use 6.251 sec

而十亿级的连续偶数的素对数量，几乎是瞬时得到：
2022092100:50:2

G(2022092100) = 10883535
G(2022092102) = 3211201
G(2022092104) = 3402638
G(2022092106) = 6874442
G(2022092108) = 3209563
G(2022092110) = 4280522
G(2022092112) = 6508994
G(2022092114) = 3986580
G(2022092116) = 3638638
G(2022092118) = 6644430
G(2022092120) = 4390651
G(2022092122) = 3208833
G(2022092124) = 7008019
G(2022092126) = 3214744
G(2022092128) = 3855963
G(2022092130) = 8570859
G(2022092132) = 3482884
G(2022092134) = 3213157
G(2022092136) = 6482214
G(2022092138) = 3777188
G(2022092140) = 4287676
G(2022092142) = 7704332
G(2022092144) = 3235219
G(2022092146) = 3279664
G(2022092148) = 6503250
G(2022092150) = 4892328
G(2022092152) = 3210046
G(2022092154) = 6437686
G(2022092156) = 3853454
G(2022092158) = 3234544
G(2022092160) = 9667534
G(2022092162) = 3237028
G(2022092164) = 3328443
G(2022092166) = 6876423
G(2022092168) = 3214374
G(2022092170) = 5164650
G(2022092172) = 6531642
G(2022092174) = 3215845
G(2022092176) = 3734260
G(2022092178) = 6422472
G(2022092180) = 4588744
G(2022092182) = 3565704
G(2022092184) = 7737386
G(2022092186) = 3283900
G(2022092188) = 3210825
G(2022092190) = 8575080
G(2022092192) = 3216869
G(2022092194) = 3232107
G(2022092196) = 6747816
G(2022092198) = 3855840

count = 50, algorithm = 2, working threads = 2, time use 0.582 sec

重生888@ · 发表于 2022-9-22 05:10

愚工688 发表于 2022-9-21 17:12
能够学会先进的编程方法就会带来不一样的体会！
这个素对筛选程序是网友深圳的黄博士赠予我的，使用C+ ...

我凭肉眼，看这组数据，就能判断以下两个偶数小素数因子多：
2022092142
2022092160

		自动登录	找回密码
密码			注册

今天2022.09.10教师节，计算一下从20220910开始的连续50个偶数的素对数量

点评

点评

本帖子中包含更多资源

点评