本帖最后由 王守恩 于 2023-4-23 07:22 编辑
6楼可以这样解决。谢谢 northwolves!
Table[ResourceFunction["NthDigit"][N[6491293100/1111111111, 2023], n], {n, 1, 30}]
{5, 8, 4, 2, 1, 6, 3, 7, 9, 0, 5, 8, 4, 2, 1, 6, 3, 7, 9, 0, 5, 8, 4, 2, 1, 6, 3, 7, 9, 0}
Table[ResourceFunction["NthDigit"][N[6491293100/1111111111,2023],n],{n,2000,2024}]
{0, 5, 8, 4, 2, 1, 6, 3, 7, 9, 0, 5, 8, 4, 2, 1, 6, 3, 7, 9, 0, 5, 8, 4, Indeterminate} |