新年一题

费尔马1

解函数不定方程:
A^（6n+3）+B^（6n+2）=C^（6n+1）
其中一个答案是：
A=2^(36n^2+12n+2)*uv*[(u^(6n+3)-v^(6n+3)]^(12n+2)*[(u^(6n+3)+v^(6n+3)]^(36n^2+12n)
B=2^(36n^2+18n+2)*[(u^(6n+3)-v^(6n+3)]^(12n+4)*[(u^(6n+3)+v^(6n+3)]^(36n^2+18n)
C=2^(36n^2+24n+4)*[(u^(6n+3)-v^(6n+3)]^(12n+6)*[(u^(6n+3)+v^(6n+3)]^(36n^2+24n+2)
其中，u、v为正整数，且u＞v

费尔马1

。。。。