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楼主 |
发表于 2024-10-3 07:06
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m t1 t2 m素性
1 2 -3 ————
13 5 -6 13 is prime
19 6 -7 19 is prime
43 9 -10 43 is prime
53 10 -11 53 is prime
89 13 -14 89 is prime
103 14 -15 103 is prime
151 17 -18 151 is prime
169 18 -19 169=13*13
229 21 -22 229 is prime
251 22 -23 251 is prime
323 25 -26 323=17*19
349 26 -27 349 is prime
433 29 -30 433 is prime
463 30 -31 463 is prime
559 33 -34 559=13*43
593 34 -35 593 is prime
701 37 -38 701 is prime
739 38 -39 739 is prime
859 41 -42 859 is prime
901 42 -43 901=17*53
1033 45 -46 1033 is prime
1079 46 -47 1079=13*83
t m1 m2
1 2 -3
4 3 -4
8 4 -5
13 5 -6
19 6 -7
26 7 -8
34 8 -9
43 9 -10
53 10 -11
64 11 -12
76 12 -13
89 13 -14
103 14 -15
118 15 -16
134 16 -17
151 17 -18
169 18 -19
188 19 -20
208 20 -21
229 21 -22
251 22 -23
274 23 -24
298 24 -25
323 25 -26
349 26 -27
376 27 -28
404 28 -29
433 29 -30
463 30 -31
494 31 -32
526 32 -33
559 33 -34
593 34 -35
628 35 -36
664 36 -37
701 37 -38
……
m2都是负数,可以不考虑,只考虑m1,
当t等于1,4,13,26,64,89时,m等于2,3,5,7,11,13是素数;
当t等于8,19,34,43,53,76,103时,m等于4,6,8,9,10,12,14不是素数,反例是不是指的它们?
还要不要补充规定一下t必须取奇素数?若如此将上面的结果改一改就是了——
当t等于13,89时,m等于5,13是素数;
当t等于19,43,53,103时,m等于6,9,10,14不是素数
杨先生,m和t是到过来使用,m换成t,t换成m,那是行不通
取一个例子
t=43,m=9,a+4m-ct= c,a+4×9-43×387=387,
a=16992,a=2mv,v=16992/2/9,v=944,v是偶数,不符合题意,假反例 |
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