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素数公式,素数判断,求证:t=p

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发表于 2024-10-26 15:35 | 显示全部楼层 |阅读模式
已知:\(a^2+ab+b^2=mt^2\),\(a=tv\),\(b=ty\),\(t\ne3c\)
\(t\ne5u\),\(\sqrt{m}\ne k\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(u>0\),\(v>0\),\(y>0\),奇数\(m>1\),\(t>1\),素数\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=mt^2\),\(a=tv\),\(b=ty\),\(t\ne3c\)
\(t\ne5u\),\(m\ne k^n\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(n>1\),\(u>0\),\(v>0\),\(y>0\),奇数\(m>1\),\(t>1\),素数\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=mt^2\),\(a=tv\),\(b=ty\),\(t\ne3c\)
\(t\ne5u\),\(\sqrt{m}\ne k\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(u>0\),\(v>0\),\(y>0\),奇数\(t>1\),素数\(m>0\),\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=mt^2\),\(a=tv\),\(b=ty\),\(t\ne3c\)
\(t\ne5u\),\(m\ne k^n\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(n>1\),\(u>0\),\(v>0\),\(y>0\),奇数\(t>1\),素数\(m>0\),\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=cm\),\(a=tv\),\(b=ty\),\(c=2^k-1\),\(c=mt\)
整数\(a>0\),\(b>0\),\(c>0\),\(t>0\),\(v>0\),\(y>0\)
素数\(k>0\),\(m>0\),\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=cm\),\(a=tv\),\(b=ty\),\(c=2^k-1\),\(c=mt\)
整数\(a>0\),\(b>0\),\(c>0\),\(m>0\),\(t>0\),\(v>0\),\(y>0\)
素数\(k>0\),\(p>0\),\(w>0\)
求证:\(m=p\),\(t=w\)
 楼主| 发表于 2024-10-26 15:37 | 显示全部楼层
本帖最后由 太阳 于 2024-10-26 15:40 编辑

已知:\(a^2+ab+b^2=mt^2\),\(a=tv\),\(t\ne3c\)
\(t\ne5u\),\(\sqrt{m}\ne k\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(u>0\),\(v>0\),奇数\(m>1\),\(t>1\),素数\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=mt^2\),\(a=tv\),\(t\ne3c\)
\(t\ne5u\),\(m\ne k^n\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(n>1\),\(u>0\),\(v>0\),奇数\(m>1\),\(t>1\),素数\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=mt^2\),\(a=tv\),\(t\ne3c\)
\(t\ne5u\),\(\sqrt{m}\ne k\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(u>0\),\(v>0\),奇数\(t>1\),素数\(m>0\),\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=mt^2\),\(a=tv\),\(t\ne3c\)
\(t\ne5u\),\(m\ne k^n\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(n>1\),\(u>0\),\(v>0\),奇数\(t>1\),素数\(m>0\),\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=cm\),\(a=tv\),\(c=2^k-1\),\(c=mt\)
整数\(a>0\),\(b>0\),\(c>0\),\(t>0\),\(v>0\)
素数\(k>0\),\(m>0\),\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=cm\),\(a=tv\),\(c=2^k-1\),\(c=mt\)
整数\(a>0\),\(b>0\),\(c>0\),\(m>0\),\(t>0\),\(v>0\)
素数\(k>0\),\(p>0\),\(w>0\)
求证:\(m=p\),\(t=w\)

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 楼主| 发表于 2024-10-26 15:37 | 显示全部楼层
本帖最后由 太阳 于 2024-10-26 18:55 编辑

已知:\(a^2+ab+b^2=mt^2\),\(b=ty\),\(t\ne3c\)
\(t\ne5u\),\(\sqrt{m}\ne k\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(u>0\),\(y>0\),奇数\(m>1\),\(t>1\),素数\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=mt^2\),\(b=ty\),\(t\ne3c\)
\(t\ne5u\),\(m\ne k^n\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(n>1\),\(u>0\),\(y>0\),奇数\(m>1\),\(t>1\),素数\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=mt^2\),\(b=ty\),\(t\ne3c\)
\(t\ne5u\),\(\sqrt{m}\ne k\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(u>0\),\(y>0\),奇数\(t>1\),素数\(m>0\),\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=mt^2\),\(b=ty\),\(t\ne3c\)
\(t\ne5u\),\(m\ne k^n\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(n>1\),\(u>0\),\(y>0\),奇数\(t>1\),素数\(m>0\),\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=cm\),\(b=ty\),\(c=2^k-1\),\(c=mt\)
整数\(a>0\),\(b>0\),\(c>0\),\(t>0\),\(y>0\)
素数\(k>0\),\(m>0\),\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=cm\),\(b=ty\),\(c=2^k-1\),\(c=mt\)
整数\(a>0\),\(b>0\),\(c>0\),\(m>0\),\(t>0\),\(y>0\)
素数\(k>0\),\(p>0\),\(w>0\)
求证:\(m=p\),\(t=w\)

回复 支持 反对

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 楼主| 发表于 2024-10-26 15:42 | 显示全部楼层
已知:\(a^2+ab+b^2=mt^2\),\(b=ty\),\(t\ne3c\)
\(t\ne5u\),\(\sqrt{m}\ne k\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(u>0\),\(y>0\),奇数\(m>1\),\(t>1\),素数\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=mt^2\),\(b=ty\),\(t\ne3c\)
\(t\ne5u\),\(m\ne k^n\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(n>1\),\(u>0\),\(y>0\),奇数\(m>1\),\(t>1\),素数\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=mt^2\),\(b=ty\),\(t\ne3c\)
\(t\ne5u\),\(\sqrt{m}\ne k\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(u>0\),\(y>0\),奇数\(t>1\),素数\(m>0\),\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=mt^2\),\(b=ty\),\(t\ne3c\)
\(t\ne5u\),\(m\ne k^n\),整数\(a>0\),\(b>0\),\(c>0\),\(k>0\)
\(n>1\),\(u>0\),\(y>0\),奇数\(t>1\),素数\(m>0\),\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=cm\),\(b=ty\),\(c=2^k-1\),\(c=mt\)
整数\(a>0\),\(b>0\),\(c>0\),\(t>0\),\(y>0\)
素数\(k>0\),\(m>0\),\(p>0\)
求证:\(t=p\)
已知:\(a^2+ab+b^2=cm\),\(b=ty\),\(c=2^k-1\),\(c=mt\)
整数\(a>0\),\(b>0\),\(c>0\),\(m>0\),\(t>0\),\(y>0\)
素数\(k>0\),\(p>0\),\(w>0\)
求证:\(m=p\),\(t=w\)
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 楼主| 发表于 2024-10-26 20:00 | 显示全部楼层
方程(13*23*(2^4243-1)/101833)^2+13*23*(2^4243-1)/101833b+b^2=(2^4243-1)*(2^4243-1)/101833
b=67699395072733261531712744359489957533165214487082505828375349175018131057320746144419066517703649420950206833096760787395947262415217219403883917417449686864265826235824640820342352435360615688418021930619515684783466660722854075628866636951359600389570246815370481349544155568843891161457067309161071616183712714246788664482864802153762291382918331042589574813158237399892460535904229002970783295766252764984647368524847269721583997503750686770825748827969122625816766776156112752404514587665991180692094763940574036357560534602811241242176750997161900512268255802785326287116019102426942637098003661367566390770677460215099576004734062241916791302604008516087068119607352517435732055312966168265540333716715776612095284146387079123434419869946132374151965657982720721252297380679976203862333831143028022573645010924120246928184512487353492760783302381770453348258467048285647714355020287076416555412315872816100205588899697881862337694678225087424864900467759915533205440310399874362742003476822344974681138615578316318049279002007647943229439634724543194265648861858634042989478565448010154537335281387766106303135486260477093072148697913464119883072667726277115153699320525686507472423581569948141015568572466018170074091111302844381992914344388899696911001357647995523
试除299次,判断(2^4243-1)/101833是素数,找到大素数有1273位
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 楼主| 发表于 2024-10-26 20:43 | 显示全部楼层
已知:\(a^2+ab+b^2=cm\),\(b=ty\),\(c=2^k-1\),\(c=mt\)
整数\(a>0\),\(b>0\),\(c>0\),\(m>0\),\(t>0\),\(y>0\)
素数\(k>0\),\(p>0\),\(w>0\)
求证:\(m=p\),\(t=w\)
方程a^2+37*(2^4243-1)/101833a+(37*(2^4243-1)/101833)^2=(2^4243-1)*(2^4243-1)/101833
a=547084300722898518864381366580743170335578354909126195748222416306227599625375759383278402399821383158489509272863012849496979228706755367615170035346417739795013028230042367710334145356022272725324015060952302425682608960976577530081922282390716770715716318859345241176046013921197931277720625011869200357808921663778102991361529076864187165499799485992818455922548999528860694600955796537520654200921880452173231437538630639101449060908687982283159429717912639597816574758666965215377023289517063865592873903195449645159745941790285435984076987787875898734275905000886825941829451665558266175467651209429793265957636773089588465551769854333327583769691852602973874804394551424683348230772348224632339453548595059649094323237019909673159230840916042699228046803698202585255051806035483377157778797615280506743779953143566319771004573884289036093897497625658528408899503984794828826814893671239150001845471512757134093813000261261536188397534845976757692033509735533633200720346204390120536730799185976957558390433997745380992822205413155000691958129260497705011594856641394023077137596458244221801709436079515291476689470050882454826282720976372212028073720274509660296110725329196371196071645659851193612297382901065752760898439987850546375172674926513766929443403695963821
试除37次,方程找到正整数解,判断(2^4243-1)/101833是素数
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 楼主| 发表于 2024-10-26 23:57 | 显示全部楼层
本帖最后由 太阳 于 2024-10-27 00:09 编辑

\(a=tv\)修改\(a=mv\),\(b=ty\)修改\(a=my\),
已知:\(a^2+ab+b^2=cm\),\(a=mv\),\(c=2^k-1\),\(c=mt\)
整数\(a>0\),\(b>0\),\(c>0\),\(m>0\),\(t>0\),\(v>0\)
素数\(k>0\),\(p>0\),\(w>0\)
求证:\(m=p\),\(t=w\)
已知:\(a^2+ab+b^2=cm\),\(b=my\),\(c=2^k-1\),\(c=mt\)
整数\(a>0\),\(b>0\),\(c>0\),\(m>0\),\(t>0\),\(y>0\)
素数\(k>0\),\(p>0\),\(w>0\)
求证:\(m=p\),\(t=w\)
回复 支持 反对

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