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这是几次方程?如何求根?

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发表于 2015-6-30 23:02 | 显示全部楼层 |阅读模式
S*X^3-R^2*X^3+(1353*5^(3/2)+15127)^(1/25)*8^(1/5)*X^3/(sqrt(5)*(11*5^(3/2)+123)^(1/5)+3*(11*5^(3/2)+123)^(1/5))^(1/5)-R*S*X^2+(1353*5^(3/2)+15127)^(1/25)*8^(1/5)*R*X^2/(sqrt(5)*(11*5^(3/2)+123)^(1/5)+3*(11*5^(3/2)+123)^(1/5))^(1/5)-(3*sqrt(5)+7)^(1/5)*65536^(1/25)*X^2/(sqrt(5)*(11*5^(3/2)+123)^(1/5)+3*(11*5^(3/2)+123)^(1/5))^(1/5)+(1353*5^(3/2)+15127)^(1/25)*8^(1/5)*S*X/(sqrt(5)*(11*5^(3/2)+123)^(1/5)+3*(11*5^(3/2)+123)^(1/5))^(1/5)+(3*sqrt(5)+7)^(1/5)*65536^(1/25)*R*X/(sqrt(5)*(11*5^(3/2)+123)^(1/5)+3*(11*5^(3/2)+123)^(1/5))^(1/5)+5*X
=0

其中:
R= ((sqrt(5)+3)^(1/5)*X^2+2^(13/25)*(5^(3/2)+11)^(2/25))/((sqrt(5)+3)^(1/5)*X)

S =(-(2*(sqrt(5)+3)^(1/5)*(5^(3/2)+11)^(2/25)*X^3+2^(13/25)*(5^(3/2)+11)^(4/25)*X-2^(12/25)*(sqrt(5)+3)^(2/5))/((sqrt(5)+3)^(1/5)*(5^(3/2)+11)^(2/25)*X))

解方程,求X.
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