数学中国

用户名  找回密码
 注册
帖子
热搜: 活动 交友 discuz
收藏本版 (78) |订阅

基础数学 今日: 1 |主题: 32817|排名: 3 

版主: luyuanhong
作者 回复/查看 最后发表
预览 设 n 阶 Hermite 方阵 H=(hij)>0 。证明:detH≤h11h22…hnn attach_img wilsony 2024-5-18 14:10 02281 wilsony 2024-5-18 14:10
预览 介 绍 复 斜 率 解 析 几 何 attach_img  ...23 天山草 2023-11-17 14:24 3410763 denglongshan 2024-5-17 20:58
预览 已知 A,B 都是 n 阶半正定矩阵,有 A≥0,B≥0,证明:det(A+B)≥detA attach_img wilsony 2024-5-15 18:27 52571 wilsony 2024-5-16 21:52
预览 用五种颜色涂下图中 A,B,C,D,E 五个区域,要求相邻区域涂不同的颜色,有几种涂法? attach_img allen125 2024-5-15 22:43 42855 allen125 2024-5-16 15:33
预览 {a(n)} 满足 a(n+1)^2-a(n+1)=2√[1+a(1)^3+a(2)^3+…+a(n)^3],a(1)=2,求通项公式 attach_img H2L 2024-5-15 00:47 52869 luyuanhong 2024-5-16 08:40
预览 袋中有三红四绿五蓝球,在红蓝绿依次取完条件下,求红球取完前至少先取到两蓝球的概率 attach_img allen125 2024-5-14 23:32 22545 allen125 2024-5-15 22:42
预览 不等式组 2x-1≥3x-5,-3x+a<2 只有三个偶数解,(y+a)/(y-2)-a/(y+2)=1解为正数,求 a attach_img jiaohuaxian2010 2024-5-1 22:18 74280 luyuanhong 2024-5-15 08:15
预览 已知实数 x,y 满足 [x-√(x^2-2024)][y-√(y^2-2024)]=2024,求 3x^2-2y^2+3x-3y-2023 attach_img wintex 2024-4-30 19:48 23646 波斯猫猫 2024-5-12 21:11
预览 证明组合求和公式 ∑(-1)^(k+1)C(n,k)/k=∑(k=1,n)1/k attach_img luyuanhong 2024-5-12 19:09 02830 luyuanhong 2024-5-12 19:09
预览 证明组合求和公式 ∑(k=0,2n)(-1)^kC(m,k)C(m,2n-k)=(-1)^nC(m,n) attach_img luyuanhong 2024-5-12 19:04 02794 luyuanhong 2024-5-12 19:04
预览 证明几个组合求和公式 attach_img Bathan_Tam 2024-5-4 14:18 94030 luyuanhong 2024-5-12 19:01
预览 圆半径为 4 ,C 是半径中点,D,E 是圆周上两点,∠DCE=30°,求 ΔDEC 面积的取值范围 attach_img Urz 2024-5-10 17:43 13235 王守恩 2024-5-12 09:35
预览 证明组合求和公式 ∑(k=0,n)kC(n,k)C(m,k)=nC(n+m-1,m-1) attach_img luyuanhong 2024-5-11 13:31 02825 luyuanhong 2024-5-11 13:31
预览 已知两圆有一个交点 (9,6),两圆半径乘积为 68 ,公切线为 x 轴和 y=mx(m>0),求 m attach_img evaQ 2024-5-5 10:05 13335 cgl_74 2024-5-10 19:04
预览 O,H为ΔABC外心和垂心,D,E,F在AB,BC,CA上,BD=DF=FE=EC,O1为ΔDEF外心,证:OO1=O1H attach_img dodonaomikiki 2022-7-27 11:50 76122 dodonaomikiki 2024-5-10 17:53
预览 求 y=|√3sinx-cosx|,x=2π 与 x,y 轴围成的区域绕 x 轴旋转一周所成旋转体的体积 attachment wintex 2024-4-21 15:09 13102 luyuanhong 2024-5-8 11:52
预览 求无穷根号求和式 √(6+2√(7+3√(8+4√(9+5√(…))))) 的值 attach_img allen125 2024-5-6 23:54 23139 allen125 2024-5-8 01:40
预览 设平面曲线参数方程为 x=x(u),y=y(u),其中 u 是弧长,证明:(dx/du)^2+(dy/du)^2=1 attach_img javavwv 2024-4-28 16:09 23148 javavwv 2024-5-7 12:06
预览 a(1)=3,b(1)=2,a(n+1)=a(n)+2b(n),b(n+1)=a(n)+b(n),证:lim(n→∞)a(n)/b(n)=√2 attach_img elim 2024-5-5 11:26 73856 luyuanhong 2024-5-6 12:28
预览 挪威测量员韦塞尔给出了向量商运算? attach_img denglongshan 2024-4-19 20:32 11940 denglongshan 2024-5-5 23:09
下一页 »

快速发帖

还可输入 80 个字符
您需要登录后才可以发帖 登录 | 注册

本版积分规则

LaTEX预览输入 教程 符号库 加行内标签 加行间标签 
对应的 LaTEX 效果:

Archiver|手机版|小黑屋|数学中国 ( 京ICP备05040119号 )

GMT+8, 2025-8-22 08:55 , Processed in 0.081824 second(s), 13 queries .

Powered by Discuz! X3.4

Copyright © 2001-2020, Tencent Cloud.

返回顶部 返回版块
\frac{\square}{\square}\sqrt{\square}\square_{\baguet}^{\baguet}\overarc{\square}\ \dot{\baguet}\left(\square\right)\binom{\square}{\square}\begin{cases}\square\\\square\end{cases}\ \begin{bmatrix}\square&\square\\\square&\square\end{bmatrix}\to\Rightarrow\mapsto\alpha\ \theta\ \pi\times\div\pm\because\angle\ \infty
\frac{\square}{\square}\sqrt{\square}\sqrt[\baguet]{\square}\square_{\baguet}\square^{\baguet}\square_{\baguet}^{\baguet}\sum_{\baguet}^{\baguet}\prod_{\baguet}^{\baguet}\coprod_{\baguet}^{\baguet}\int_{\baguet}^{\baguet}\lim_{\baguet}\lim_{\baguet}^{\baguet}\bigcup_{\baguet}^{\baguet}\bigcap_{\baguet}^{\baguet}\bigwedge_{\baguet}^{\baguet}\bigvee_{\baguet}^{\baguet}
\underline{\square}\overline{\square}\overrightarrow{\square}\overleftarrow{\square}\overleftrightarrow{\square}\underrightarrow{\square}\underleftarrow{\square}\underleftrightarrow{\square}\dot{\baguet}\hat{\baguet}\vec{\baguet}\tilde{\baguet}
\left(\square\right)\left[\square\right]\left\{\square\right\}\left|\square\right|\left\langle\square\right\rangle\left\lVert\square\right\rVert\left\lfloor\square\right\rfloor\left\lceil\square\right\rceil\binom{\square}{\square}\boxed{\square}
\begin{cases}\square\\\square\end{cases}\begin{matrix}\square&\square\\\square&\square\end{matrix}\begin{pmatrix}\square&\square\\\square&\square\end{pmatrix}\begin{bmatrix}\square&\square\\\square&\square\end{bmatrix}\begin{Bmatrix}\square&\square\\\square&\square\end{Bmatrix}\begin{vmatrix}\square&\square\\\square&\square\end{vmatrix}\begin{Vmatrix}\square&\square\\\square&\square\end{Vmatrix}\begin{array}{l|l}\square&\square\\\hline\square&\square\end{array}
\to\gets\leftrightarrow\nearrow\searrow\downarrow\uparrow\updownarrow\swarrow\nwarrow\Leftarrow\Rightarrow\Leftrightarrow\rightharpoonup\rightharpoondown\impliedby\implies\Longleftrightarrow\leftharpoonup\leftharpoondown\longleftarrow\longrightarrow\longleftrightarrow\Uparrow\Downarrow\Updownarrow\hookleftarrow\hookrightarrow\mapsto
\alpha\beta\gamma\Gamma\delta\Delta\epsilon\varepsilon\zeta\eta\theta\Theta\iota\kappa\varkappa\lambda\Lambda\mu\nu\xi\Xi\pi\Pi\varpi\rho\varrho\sigma\Sigma\tau\upsilon\Upsilon\phi\Phi\varphi\chi\psi\Psi\omega\Omega\digamma\vartheta\varsigma\mathbb{C}\mathbb{H}\mathbb{N}\mathbb{P}\mathbb{Q}\mathbb{R}\mathbb{Z}\Re\Im\aleph\partial\nabla
\times\cdot\ast\div\pm\mp\circ\backslash\oplus\ominus\otimes\odot\bullet\varnothing\neq\equiv\not\equiv\sim\approx\simeq\cong\geq\leq\ll\gg\succ\prec\in\ni\cup\cap\subset\supset\not\subset\not\supset\notin\not\ni\subseteq\supseteq\nsubseteq\nsupseteq\sqsubset\sqsupset\sqsubseteq\sqsupseteq\sqcap\sqcup\wedge\vee\neg\forall\exists\nexists\uplus\bigsqcup\bigodot\bigotimes\bigoplus\biguplus\bigcap\bigcup\bigvee\bigwedge
\because\therefore\angle\parallel\perp\top\nparallel\measuredangle\sphericalangle\diamond\diamondsuit\doteq\propto\infty\bowtie\square\smile\frown\bigtriangledown\triangle\triangleleft\triangleright\bigcirc \wr\amalg\models\preceq\mid\nmid\vdash\dashv\nless\ngtr\ldots\cdots\vdots\ddots\surd\ell\flat\sharp\natural\wp\clubsuit\heartsuit\spadesuit\oint\lfloor\rfloor\lceil\rceil\lbrace\rbrace\lbrack\rbrack\vert\hbar\aleph\dagger\ddagger

MathQuill输入:

Latex代码输入: