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本帖最后由 愚工688 于 2021-1-5 14:25 编辑
以今天日期的百倍为随机偶数的连续偶数的素对下界计算值的计算:
G(2021010500) = 4289434;
inf( 2021010500 )≈ 4262261.1 , jd ≈0.993665,infS(m) = 3188752.43 , k(m)= 1.33665
G(2021010502) = 3853489;
inf( 2021010502 )≈ 3827411.6 , jd ≈0.993233,infS(m) = 3188752.44 , k(m)= 1.20028
G(2021010504) = 6417248;
inf( 2021010504 )≈ 6377504.9 , jd ≈0.993807,infS(m) = 3188752.44 , k(m)= 2
G(2021010506) = 3560955;
inf( 2021010506 )≈ 3537103.6 , jd ≈0.993302,infS(m) = 3188752.44 , k(m)= 1.10924
G(2021010508) = 3566828;
inf( 2021010508 )≈ 3543058.3 , jd ≈0.993336,infS(m) = 3188752.45 , k(m)= 1.11111
G(2021010510) = 8594792;
inf( 2021010510 )≈ 8541132.5 , jd ≈0.993757,infS(m) = 3188752.45 , k(m)= 2.67852
G(2021010512) = 3259421;
inf( 2021010512 )≈ 3237810.2 , jd ≈0.993370,infS(m) = 3188752.45 , k(m)= 1.01538
G(2021010514) = 3218269;
inf( 2021010514 )≈ 3196587.2 , jd ≈0.993263,infS(m) = 3188752.46 , k(m)= 1.00246
G(2021010516) = 7757896;
inf( 2021010516 )≈ 7708867.3 , jd ≈0.993680,infS(m) = 3188752.46 , k(m)= 2.41752
G(2021010518) = 3208538;
inf( 2021010518 )≈ 3188752.5 , jd ≈0.993833,infS(m) = 3188752.46 , k(m)= 1
G(2021010520) = 4398552
inf( 2021010520 )≈ 4369756.9 , jd ≈0.993454,infS(m) = 3188752.46 , k(m)= 1.37037
G(2021010522) = 6983089;
inf( 2021010522 )≈ 6937229.1 , jd ≈0.993433,infS(m) = 3188752.47 , k(m)= 2.17553
计算值的计算精度没有一个低于99%的。
偶数素对下界计算式:
inf( 2021010500 ) = 1/(1+ .148 )*( 2021010500 /2 -2)*p(m) ≈ 4262261.1
inf( 2021010502 ) = 1/(1+ .148 )*( 2021010502 /2 -2)*p(m) ≈ 3827411.6
inf( 2021010504 ) = 1/(1+ .148 )*( 2021010504 /2 -2)*p(m) ≈ 6377504.9
inf( 2021010506 ) = 1/(1+ .148 )*( 2021010506 /2 -2)*p(m) ≈ 3537103.6
inf( 2021010508 ) = 1/(1+ .148 )*( 2021010508 /2 -2)*p(m) ≈ 3543058.3
inf( 2021010510 ) = 1/(1+ .148 )*( 2021010510 /2 -2)*p(m) ≈ 8541132.5
inf( 2021010512 ) = 1/(1+ .148 )*( 2021010512 /2 -2)*p(m) ≈ 3237810.2
inf( 2021010514 ) = 1/(1+ .148 )*( 2021010514 /2 -2)*p(m) ≈ 3196587.2
inf( 2021010516 ) = 1/(1+ .148 )*( 2021010516 /2 -2)*p(m) ≈ 7708867.3
inf( 2021010518 ) = 1/(1+ .148 )*( 2021010518 /2 -2)*p(m) ≈ 3188752.5
inf( 2021010520 ) = 1/(1+ .148 )*( 2021010520 /2 -2)*p(m) ≈ 4369756.9
inf( 2021010522 ) = 1/(1+ .148 )*( 2021010522 /2 -2)*p(m) ≈ 6937229.1
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