fungarwai 发表于 2021-1-31 08:26 咦?唔係喎,有問題 \((\sqrt{x^n}+\sqrt{x/4})^2=x^n+(\sqrt{x^{n+1}}+x/4)\) 你個遞推式前面果個x/4 ...
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fungarwai 发表于 2021-1-31 10:17 sulley.cc/2020/09/infinite-radicals/ \(x(2^n+x)=x\sqrt{2^{2n}+x(2^{n+1}+x)}\)
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