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发表于 2022-8-8 21:21
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本帖最后由 愚工688 于 2022-8-10 03:58 编辑
使用连乘式计算偶数素对下界值,可以从排除了波动系数 k(m)影响的区域下界计算值infS(m)上面看出其数值的变化意味着什么?
以今天日期的百倍作随机偶数,计算连续偶数的素对的下界值inf(M),区域下界值infS(m),看看情况怎么样?
区域下界值infS(m)= inf(M)/ k(m)
inf( 2022080800 )≈ 4293481.0 , jd ≈0.99395 ,infS(m) = 3190157.32 , k(m)= 1.34585
inf( 2022080802 )≈ 7733714.7 , jd ≈0.99367 ,infS(m) = 3190157.32 , k(m)= 2.42424
inf( 2022080804 )≈ 3395501.9 , jd ≈0.99362 ,infS(m) = 3190157.33 , k(m)= 1.06437
inf( 2022080806 )≈ 3190157.3 , jd ≈0.99374 ,infS(m) = 3190157.33 , k(m)= 1
inf( 2022080808 )≈ 7094372.6 , jd ≈0.99354 ,infS(m) = 3190157.33 , k(m)= 2.22383
inf( 2022080810 )≈ 4537112.7 , jd ≈0.99357 ,infS(m) = 3190157.33 , k(m)= 1.42222
inf( 2022080812 )≈ 3261049.7 , jd ≈0.99340 ,infS(m) = 3190157.34 , k(m)= 1.02222
inf( 2022080814 )≈ 7369775.3 , jd ≈0.99360 ,infS(m) = 3190157.34 , k(m)= 2.31016
inf( 2022080816 )≈ 3856131.8 , jd ≈0.99387 ,infS(m) = 3190157.34 , k(m)= 1.20876
inf( 2022080818 )≈ 3247617.5 , jd ≈0.99310 ,infS(m) = 3190157.35 , k(m)= 1.01801
inf( 2022080820 )≈ 8507086.3 , jd ≈0.99375 ,infS(m) = 3190157.35 , k(m)= 2.66667
inf( 2022080822 )≈ 3190157.4 , jd ≈0.99368 ,infS(m) = 3190157.35 , k(m)= 1
inf( 2022080824 )≈ 3191886.4 , jd ≈0.99365 ,infS(m) = 3190157.36 , k(m)= 1.00054
inf( 2022080826 )≈ 6488455.7 , jd ≈0.99358 ,infS(m) = 3190157.36 , k(m)= 2.0339
inf( 2022080828 )≈ 3191606.8 , jd ≈0.99353 ,infS(m) = 3190157.36 , k(m)= 1.00045
inf( 2022080830 )≈ 5671390.9 , jd ≈0.99345 ,infS(m) = 3190157.37 , k(m)= 1.77778
inf( 2022080832 )≈ 6380314.7 , jd ≈0.99364 ,infS(m) = 3190157.37 , k(m)= 2
time start =20:35:50 ,time end =20:37:11 ,time use =
2022080800:18:2 素对真值
G(2022080800) = 4319625
G(2022080802) = 7782973
G(2022080804) = 3417317
G(2022080806) = 3210250
G(2022080808) = 7140488
G(2022080810) = 4566497
G(2022080812) = 3282705
G(2022080814) = 7417278
G(2022080816) = 3879932
G(2022080818) = 3270184
G(2022080820) = 8560608
G(2022080822) = 3210432
G(2022080824) = 3212292
G(2022080826) = 6530403
G(2022080828) = 3212399
G(2022080830) = 5708763
G(2022080832) = 6421155
G(2022080834) = 3478167
count = 18, algorithm = 2, working threads = 2, time use 0.646 sec
可以从区域下界计算值上面看出,其数值是随着偶数的增大而缓慢的线性增大的,大约每3个多一点偶数的区域下界计算值约增大0.01,这意味着偶数越大,区域下界计算值也就越大,大偶数的哥德巴赫猜想必定成立。因为素对真值始终大于区域下界值。
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