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楼主: kindlychung

请教数学分析习题

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发表于 2010-9-24 21:44 | 显示全部楼层

请教数学分析习题


The way of getting through those topics is to write things explicitly according to definitions and then manipulate them according to established laws.
Those topics are quite mechanical, although a little abstract, but not really tough.

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 楼主| 发表于 2010-9-25 01:49 | 显示全部楼层

请教数学分析习题

Love explanation. Many thanks.
Here comes another.
Since N is an inductive set and N is infinite, why can';t induction be used to prove this?

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发表于 2010-9-25 07:50 | 显示全部楼层

请教数学分析习题

Math Induction can only be used to show proposition with parameter n is true for all n in N. Since ∞ is not in N, (b) cannot be proven by induction
(c) the equality in (b) is valid:

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 楼主| 发表于 2010-9-26 01:08 | 显示全部楼层

请教数学分析习题

Why is infinity not in N? n can get infinitely large.
发表于 2010-9-26 01:57 | 显示全部楼层

请教数学分析习题

下面引用由kindlychung2010/09/26 01:08am 发表的内容:
Why is infinity not in N? n can get infinitely large.
But not infinite itself
 楼主| 发表于 2010-9-26 13:20 | 显示全部楼层

请教数学分析习题

What do you mean "infinite itself"? Please give a definition.
发表于 2010-9-27 13:05 | 显示全部楼层

请教数学分析习题

N does not contain infinite itself
 楼主| 发表于 2010-9-27 13:55 | 显示全部楼层

请教数学分析习题

Again, we need to agree on the definition of "infinite itself", to determine whether it';s contained in a set, we have to first define what it is.
After that I';d like to know what set contain infinite itself? Does R?
发表于 2010-9-27 14:06 | 显示全部楼层

请教数学分析习题

Good thoughts. But since infinite is not a number in your book, therefore N does not contain it and so induction does not work here.
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