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天下的朋友们!设想五次方程公式解存在那数学世界将怎么样

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发表于 2016-9-4 20:10 | 显示全部楼层 |阅读模式
作者进过几年的探索!发现一元五次方程有已知常数的模式解!而且有可能存在公式普遍解
发表于 2016-9-4 23:11 | 显示全部楼层



一元五次的基本就是这个模样:



32*x^5-160*x-79=0的根就是这个样子:

x1=(实数)
(2*5^(1/2)+6-2*(8*(125^(1/2)+11)^2)^(1/5))
/(5*(8*(125^(1/2)+11)^2)^(1/5)-5*5^(1/2)-15)

x2 = (虚数)
(-sqrt((-(15*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/6))/(8*sqrt(144*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(2/3)-15*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3)-950)))-(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3)+475/(72*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3))-5/24)/2)-sqrt(144*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(2/3)-15*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3)-950)/(24*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/6))+1/8

x3=(虚数)
sqrt((-(15*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/6))/(8*sqrt(144*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(2/3)-15*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3)-950)))-(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3)+475/(72*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3))-5/24)/2-sqrt(144*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(2/3)-15*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3)-950)/(24*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/6))+1/8

x4=(实数)
(-sqrt((15*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/6))/(8*sqrt(144*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(2/3)-15*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3)-950))-(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3)+475/(72*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3))-5/24)/2)+sqrt(144*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(2/3)-15*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3)-950)/(24*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/6))+1/8

x5=(实数)
sqrt((15*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/6))/(8*sqrt(144*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(2/3)-15*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3)-950))-(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3)+475/(72*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3))-5/24)/2+sqrt(144*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(2/3)-15*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/3)-950)/(24*(3575/3456+(175*sqrt(4163))/(128*3^(3/2)))^(1/6))+1/8

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发表于 2016-9-5 07:08 | 显示全部楼层

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发表于 2016-9-5 09:10 | 显示全部楼层
勾股定理~数据报废~不可靠~错误
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