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数学题数论

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发表于 2013-10-25 21:55 | 显示全部楼层 |阅读模式
已知:a>0,b>0,c>0,d>0,e>0,a≠d,a^2+b^2=c^2=d^2+e^2
求证:a+b≠c+d,b+c≠d+e,b+d≠c+e
已知:a>0,b>0,c>0,d>0,e>0,a^2+b^2=c^2=d^2-e^2
求证:a≠b≠c,a+b≠d,a+b+c≠d+e
求证:a+b≠e,b+c≠d,a+b≠c+e
已知:a>0,b>0,c>0,d>0,e>0,a≠d,a^2-b^2=c^2=d^2-e^2,或(a^2-b^2=c^2=d^2+e^2)
求证:a-b≠d-e,a+b≠d+e,a≠e,a-b≠d+e,b+e≠d,b+d≠c,b+e≠c,a-e≠d,b+e≠a
已知:a>0,b>0,c>0,d>0,e>0,a≠d,a^3+b^3=c^3=d^3+e^3
求证:a+b≠c+d,b+c≠d+e,b+d≠c+e
已知:a>0,b>0,c>0,d>0,e>0,整数f>1,f>2,或(分数f>0),a≠d,a^f+b^f=c^f=d^f-e^f,或(a^f-b^f=c^f=d^f-e^f,
求证:a+b≠c+d,b+c≠d+e,b+d≠c+e,a≠b≠c,a+b≠d,a+b+c≠d+e
 楼主| 发表于 2013-10-25 22:30 | 显示全部楼层

数学题数论

f>0,a≠b,a^f+b^f=c^f=d^f+e^f,a^f+b^f=c^f=d^f-e^f,a^f-b^f=c^f=d^f-e^f,a^f-b^f=c^f=d^f+e^f
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