\[n∈N,sgn[sin(2^n)]-sgn[1-2×\{\frac{2^{n-1}}{\pi}\}]=0,\{x\},为取x小数部分\]

awei

\[\{x\},花括号为取x小数部分,sgn[x]为符号函数。\]
\[n∈N,\;\;sgn[sin(2^n)]-sgn[1-2×\{\frac{2^{n-1}}{\pi}\}]=0\]
简单明了，

awei

\[\{x\},花括号为取x小数部分,sgn[x]为符号函数。\]
\[x∈R,\;\;sgn[sin(2^x)]-sgn[1-2×\{\frac{2^{x-1}}{\pi}\}]=0\]
确切的应该这样写，