使用道具 举报
elim 发表于 2022-7-1 09:32 \(\because\;\;\displaystyle\lim_{x\to 0}\frac{\sin 2x-x}{x}=2-1=1\quad\therefore\;\;\sin 2x-x\sim x ...
本版积分规则 发表回复 回帖并转播 回帖后跳转到最后一页
Archiver|手机版|小黑屋|数学中国 ( 京ICP备05040119号 )
GMT+8, 2025-6-30 06:42 , Processed in 0.080294 second(s), 15 queries .
Powered by Discuz! X3.4
Copyright © 2001-2020, Tencent Cloud.