求 f(x,y) 和 g(x,y) 使得 √(x^2+y^2)≈f(x,y)x+g(x,y)y

rounderm

有偿跪求\(\sqrt{x^2+y^2}\)\(\)近似成\(f\left( x{,}y\right)\cdot x+g\left( x{,}y\right)\cdot y\)

Future_maths

\(f\left( x{,}y\right)=\frac{x}{\sqrt{x^2+y^2}}{,}\ \ g\left( x{,}y\right)=\frac{y}{\sqrt{x^2+y^2}}\)