设 f(x)=x(x+1)(x+2)…(x+n) ，求 f ' (0)

chenjiahao

\(设f\left( x\right)=x\left( x+1\right)\left( x+2\right)\cdots\left( x+n\right)\)
\(求f’\left( 0\right)\)

Future_maths

计算结果\(=n!\)

luyuanhong