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发表于 2020-12-20 02:52
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缺二次项的一元三次方程求解:
输入1: a=1, b=, c=-10, d=5; 输出结果1: x1=-3.3876190585, x2=0.5135435270, x3=2.8740755315 m=-540 n=1198.4990613263i
输入2: a=1, b=, c=-5, d=5; 输出结果2: x1=-2.6273650847, x2=1.3136825424+0.4210528070i, x3=1.3136825424-0.4210528070i m=-540 n=274.9545416973
输入3: a=1, b=, c=-6, d=5; 输出结果3: x1=-2.7912878475, x2=1, x3=1.7912878475 m=-540 n=285.7411415950i 输入4: a=1, b=, c=-4, d=5;
输出结果4: x1=-2.4566783430, x2=1.2283391715+0.7255696802i, x3=1.2283391715-0.7255696802i m=-540 n=425.4503496297
输入5: a=1, b=, c=-4, d=3; 输出结果5: x1=-2.3027756377, x2=1, x3=1.3027756377 m=-324 n=74.9399759808i
输入6: a=1, b=, c=-4, d=1; 输出结果6: x1=-2.0875229935, x2=0.1883751434, x3=1.8991478502 m=-108 n=314.5282181299i
输入7: a=1, b=, c=-2, d=1; 输出结果7: x1=-1.6180339887, x2=0.6180339887, x3=1 m=-108 n=46.4758001545i
输入8: a=1, b=, c=-1, d=1; 输出结果8: x1=-1.3247179572, x2=0.6623589786+0.5622795121i, x3=0.6623589786-0.5622795121i m=-108 n=99.6794863550
输入9: a=1, b=, c=-1.5, d=1; 输出结果9: x1=-1.4756865178, x2=0.7378432589+0.3650178408i, x3=0.7378432589-0.3650178408i m=-108 n=76.3675323681
输入10: a=1, b=, c=-1.8, d=1; 输出结果10: x1=-1.5621021143, x2=0.7810510571+0.1735576608i, x3=0.7810510571-0.1735576608i m=-108 n=39.8284320555
输入11: a=1, b=, c=-1.9, d=1; 输出结果11: x1=-1.5902323492, x2=0.7370575258, x3=0.8531748234 m=-108 n=13.7241393173i |
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