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这里有 1,2,3 三串数,第1串是主帖,
三串数的分母相同,分子的比=5:3:1
答案好像是2:1:0(即每串数的第1个数)。
1,\(\displaystyle\sum_{k = 0}^n\ \frac{k\ !\ (n-k)\ !}{n\ !}\), {n, 1, 16}
{2, 5/2, 8/3, 8/3, 13/5, 151/60, 256/105, 83/35, 146/63, 1433/630, 2588/1155,
15341/6930, 28211/12870, 52235/24024, 19456/9009, 19345/9009}
2,\(\displaystyle\sum_{k = 1}^n\ \frac{k\ !\ (n-k)\ !}{n\ !}\), {n, 1, 16}
{1, 3/2, 5/3, 5/3, 8/5, 91/60, 151/105, 48/35, 83/63, 803/630, 1433/1155,
8411/6930, 15341/12870, 28211/24024, 10447/9009, 10336/9009}
3,\(\displaystyle\sum_{k = 1}^{n-1}\ \frac{k\ !\ (n-k)\ !}{n\ !}\), {n, 1, 16}
{0, 1/2, 2/3, 2/3, 3/5, 31/60, 46/105, 13/35, 20/63, 173/630, 278/1155,
1481/6930, 2471/12870, 4187/24024, 1438/9009, 1327/9009} |
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