\(\displaystyle求和\ \sum_{n=1}^\infty\frac{n+1}{a^n}=\frac{2a-1}{(a-1)^2}\)
- Table[Sum[(n + 1)/a^n, {n, \[Infinity]}], {a, 2, 15}]
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{3, 5/4, 7/9, 9/16, 11/25, 13/36, 15/49, 17/64, 19/81, 21/100, 23/121, 25/144, 27/169, 29/196}
一些题目跟着电脑揣摩揣摩,可以有想法。一些题目跟着电脑揣摩揣摩,还是不能揣摩什么。
- Table[Round[N[Sum[a^n/n^n, {n, \[Infinity]}]]], {a, 1, 29}]
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{1, 3, 7, 12, 20, 32, 51, 79, 122, 187, 284, 429, 647, 971, 1454, 2171, 3235, 4812, 7145,
10595, 15690, 23207, 34290, 50615, 74647, 109998, 161967, 238324, 350448} |