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楼主 |
发表于 2020-6-26 10:22
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√3 的有理逼近算法
若 1=Abs[3*A^2 - B^2](0<A<B),则 lim B/A = √3
1-----A=1 , B=2 (B/A =2.0000000000)
2-----A=4 , B=7 (B/A =1.7500000000)
3-----A=15 , B=26 (B/A =1.7333333333)
4-----A=56 , B=97 (B/A =1.7321428571)
5-----A=209 , B=362 (B/A =1.7320574163)
6-----A=780 , B=1351 (B/A =1.7320512821)
7-----A=2911 , B=5042 (B/A =1.7320508416)
递推公式:
A0=0, A1=1, A2=4, A(n+1)=4*An - A(n-1) ,
B0=1, B1=2, B2=7, B(n+1)=4*Bn - B(n-1) .
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