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发表于 2020-12-14 21:23
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本帖最后由 愚工688 于 2020-12-14 13:45 编辑
以今天日期的百倍开始的偶数的素对计算:
Xi(M)=t2*c1*M/(logM)^2
G( 2020121400 ) = ? ;Xi(M)≈ 9545920.32 δxi(M)≈?
G( 2020121402 ) = ? ;Xi(M)≈ 3543082.76 δxi(M)≈?
G( 2020121404 ) = ? ;Xi(M)≈ 3849594.64 δxi(M)≈?
G( 2020121406 ) = ? ;Xi(M)≈ 6460875.5 δxi(M)≈?
G( 2020121408 ) = ? ;Xi(M)≈ 3253178.64 δxi(M)≈?
G( 2020121410 ) = ? ;Xi(M)≈ 4293715.6 δxi(M)≈?
G( 2020121412 ) = ? ;Xi(M)≈ 6606137.5 δxi(M)≈?
G( 2020121414 ) = ? ;Xi(M)≈ 3347975.59 δxi(M)≈?
G( 2020121416 ) = ? ;Xi(M)≈ 3237976.83 δxi(M)≈?
G( 2020121418 ) = ? ;Xi(M)≈ 8151098.44 δxi(M)≈?
time start =21:24:16, time end =21:24:47
同样这些偶数,使用连乘式计算它们的素对下界值:
G(2020121400) = 9548099;
inf( 2020121400 )≈ 9484907.4 , Δ≈-0.006618 ,infS(m) = 3187491.42 , k(m)= 2.97567
G(2020121402) = 3543669;
inf( 2020121402 )≈ 3520437 , Δ≈-0.006556 ,infS(m) = 3187491.43 , k(m)= 1.10445
G(2020121404) = 3849708;
inf( 2020121404 )≈ 3824989.7 , Δ≈-0.006421 ,infS(m) = 3187491.43 , k(m)= 1.2
G(2020121406) = 6463449;
inf( 2020121406 )≈ 6419580.5 , Δ≈-0.006787 ,infS(m) = 3187491.43 , k(m)= 2.01399
G(2020121408) = 3252718;
inf( 2020121408 )≈ 3232385.7 , Δ≈-0.006251 ,infS(m) = 3187491.44 , k(m)= 1.01408
G(2020121410) = 4295374;
inf( 2020121410 )≈ 4266272.1 , Δ≈-0.006775 ,infS(m) = 3187491.44 , k(m)= 1.33844
G(2020121412) = 6607402;
inf( 2020121412 )≈ 6563914.3 , Δ≈-0.006582 ,infS(m) = 3187491.44 , k(m)= 2.05927
G(2020121414) = 3347483;
inf( 2020121414 )≈ 3326576.8 , Δ≈-0.006245 ,infS(m) = 3187491.45 , k(m)= 1.04363
G(2020121416) = 3236595;
inf( 2020121416 )≈ 3217281.1 , Δ≈-0.005967 ,infS(m) = 3187491.45 , k(m)= 1.00935
G(2020121418) = 8151883;
inf( 2020121418 )≈ 8099000.6 , Δ≈-0.006487 ,infS(m) = 3187491.45 , k(m)= 2.54087
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