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我使用连乘式对连续偶数的素数对数量的下界计算值的计算:
G(8888888888) = 14027804 ;inf( 8888888888 )≈ 13981567.4 , jd ≈0.99670 ,infS(m) = 12222040.55 ,
G(8888888890) = 21691951 ;inf( 8888888890 )≈ 21612241.6 , jd ≈0.99633 ,infS(m) = 12222040.55 ,
G(8888888892) = 26766820 ;inf( 8888888892 )≈ 26673443.3 , jd ≈0.99651 ,infS(m) = 12222040.55 ,
G(8888888894) = 12267530 ;inf( 8888888894 )≈ 12222040.6 , jd ≈0.99629 ,infS(m) = 12222040.55 ,
G(8888888896) = 12379038 ;inf( 8888888896 )≈ 12338440.9 , jd ≈0.99672 ,infS(m) = 12222040.56 ,
G(8888888898) = 24565797 ;inf( 8888888898 )≈ 24479051.2 , jd ≈0.99647 ,infS(m) = 12222040.56 ,
G(8888888900) = 16417587 ;inf( 8888888900 )≈ 16361500.1 , jd ≈0.99658 ,infS(m) = 12222040.56 ,
G(8888888902) = 12990520 ;inf( 8888888902 )≈ 12947685.8 , jd ≈0.99670 ,infS(m) = 12222040.57 ,
G(8888888904) = 29439881 ;inf( 8888888904 )≈ 29332897.4 , jd ≈0.99637 ,infS(m) = 12222040.57 ,
G(8888888906) = 13316812 ;inf( 8888888906 )≈ 13265559.8 , jd ≈0.99615 ,infS(m) = 12222040.57 ,
time start =16:16:01 ,time end =16:18:53 ,time use =
计算式:
inf( 8888888888 ) = 1/(1+ .153 )*( 8888888888 /2 -2)*p(m) ≈ 13981567.4
inf( 8888888890 ) = 1/(1+ .153 )*( 8888888890 /2 -2)*p(m) ≈ 21612241.6
inf( 8888888892 ) = 1/(1+ .153 )*( 8888888892 /2 -2)*p(m) ≈ 26673443.3
inf( 8888888894 ) = 1/(1+ .153 )*( 8888888894 /2 -2)*p(m) ≈ 12222040.6
inf( 8888888896 ) = 1/(1+ .153 )*( 8888888896 /2 -2)*p(m) ≈ 12338440.9
inf( 8888888898 ) = 1/(1+ .153 )*( 8888888898 /2 -2)*p(m) ≈ 24479051.2
inf( 8888888900 ) = 1/(1+ .153 )*( 8888888900 /2 -2)*p(m) ≈ 16361500.1
inf( 8888888902 ) = 1/(1+ .153 )*( 8888888902 /2 -2)*p(m) ≈ 12947685.8
inf( 8888888904 ) = 1/(1+ .153 )*( 8888888904 /2 -2)*p(m) ≈ 29332897.4
inf( 8888888906 ) = 1/(1+ .153 )*( 8888888906 /2 -2)*p(m) ≈ 13265559.8
inf( 8888888908 ) = 1/(1+ .153 )*( 8888888908 /2 -2)*p(m) ≈ 12251350
inf( 8888888910 ) = 1/(1+ .153 )*( 8888888910 /2 -2)*p(m) ≈ 36594647.8
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