哥德巴赫猜想的“1+1”的必然途径——变量与偶数半值不构成同余关系

yangchuanju · 发表于 2023-11-19 11:30

偶数素数定理素数个数定理数/实际数 A006880
10 4.342944819 4 1.085736205 1 4
100 21.7147241 25 0.868588964 2 25
1000 144.7648273 168 0.861695401 3 168
10000 1085.736205 1229 0.883430598 4 1229
100000 8685.889638 9592 0.905534783 5 9592
1000000 72382.41365 78498 0.922092457 6 78498
10000000 620420.6884 664579 0.933554458 7 664579
100000000 5428681.024 5761455 0.94224133 8 5761455
1000000000 48254942.43 50847534 0.949012442 9 50847534
10000000000 434294481.9 455052511 0.954383223 10 455052511
1E+11 3948131654 4118054813 0.958737033 11 4118054813
1E+12 36191206825 37607912018 0.962329597 12 37607912018
1E+13 3.34073E+11 3.46066E+11 0.965345123 13 346065536839
1E+14 3.1021E+12 3.20494E+12 0.967912581 14 3204941750802
1E+15 2.8953E+13 2.98446E+13 0.970125053 15 29844570422669
1E+16 2.71434E+14 2.79238E+14 0.97205151 16 279238341033925
1E+17 2.55467E+15 2.62356E+15 0.973744146 17 2623557157654233
1E+18 2.41275E+16 2.474E+16 0.975243161 18 24739954287740860
1E+19 2.28576E+17 2.34058E+17 0.976580027 19 234057667276344607
1E+20 2.17147E+18 2.22082E+18 0.977779738 20 2220819602560918840
1E+21 2.06807E+19 2.11273E+19 0.978862395 21 21127269486018731928
1E+22 1.97407E+20 2.01467E+20 0.979844351 22 201467286689315906290
1E+23 1.88824E+21 1.92532E+21 0.980739043 23 1925320391606803968923
1E+24 1.80956E+22 1.84356E+22 0.981557619 24 18435599767349200867866
1E+25 1.73718E+23 1.76846E+23 0.982309404 25 176846309399143769411680
1E+26 1.67036E+24 1.69925E+24 0.983002257 26 1699246750872437141327603
1E+27 1.6085E+25 1.63525E+25 0.983642852 27 16352460426841680446427399
1E+28 1.55105E+26 1.57589E+26 0.984236889 28 157589269275973410412739598
1E+29 1.49757E+27 1.5207E+27 0.984789268 29 1520698109714272166094258063

愚工688 · 发表于 2023-11-21 13:46

本帖最后由愚工688 于 2023-11-21 06:37 编辑

连乘式计算素对下界值：
在【1500000000,7500000000】区域，使用μ=0.148来修正连乘式的相对误差，得到素数下界计算值：
inf( 6000000000 ) = 1/(1+ .148 )*( 6000000000 /2 -2)*p(m) ≈ 22875441.7
inf( 6000000002 ) = 1/(1+ .148 )*( 6000000002 /2 -2)*p(m) ≈ 8579421.3
inf( 6000000004 ) = 1/(1+ .148 )*( 6000000004 /2 -2)*p(m) ≈ 8578290.6
inf( 6000000006 ) = 1/(1+ .148 )*( 6000000006 /2 -2)*p(m) ≈ 26423472.7
inf( 6000000008 ) = 1/(1+ .148 )*( 6000000008 /2 -2)*p(m) ≈ 8951259.8
inf( 6000000010 ) = 1/(1+ .148 )*( 6000000010 /2 -2)*p(m) ≈ 11437720.9
inf( 6000000012 ) = 1/(1+ .148 )*( 6000000012 /2 -2)*p(m) ≈ 17597414
inf( 6000000014 ) = 1/(1+ .148 )*( 6000000014 /2 -2)*p(m) ≈ 8597920.6
inf( 6000000016 ) = 1/(1+ .148 )*( 6000000016 /2 -2)*p(m) ≈ 8723685.4
inf( 6000000018 ) = 1/(1+ .148 )*( 6000000018 /2 -2)*p(m) ≈ 18032491.1
inf( 6000000020 ) = 1/(1+ .148 )*( 6000000020 /2 -2)*p(m) ≈ 13725265.1
inf( 6000000022 ) = 1/(1+ .148 )*( 6000000022 /2 -2)*p(m) ≈ 8579807.1
计算值精度：
G(6000000000) = 22899781 ；inf( 6000000000 )≈  22875441.7 , jd ≈0.99894；
G(6000000002) = 8585981  ；inf( 6000000002 )≈  8579421.3  , jd ≈0.99924；
G(6000000004) = 8588030  ；inf( 6000000004 )≈  8578290.6  , jd ≈0.99887；
G(6000000006) = 26447626 ；inf( 6000000006 )≈  26423472.7 , jd ≈0.99909；
G(6000000008) = 8957244  ；inf( 6000000008 )≈  8951259.8  , jd ≈0.99933；
G(6000000010) = 11446102 ；inf( 6000000010 )≈  11437720.9 , jd ≈0.99927；
G(6000000012) = 17617549 ；inf( 6000000012 )≈  17597414 , jd ≈0.99886；
G(6000000014) = 8605694  ；inf( 6000000014 )≈  8597920.6  , jd ≈0.99910；
G(6000000016) = 8729012  ；inf( 6000000016 )≈ 8723685.4 ，jd ≈0.99939；
G(6000000018) = 18046111 ；inf( 6000000018 )≈ 18032491.1  ，jd ≈0.99925；
G(6000000020) = 13738256 ；inf( 6000000020 )≈ 13725265.1  ，jd ≈0.99905；
G(6000000022) = 8586483  ；inf( 6000000022 )≈ 8579807.1 ，jd ≈0.99922；

G(7000000000) = 15799407 ；inf( 7000000000 )≈  15792383.3 , jd ≈0.99956 ,infS(m) = 9870239.58 ,
G(7000000002) = 21065599 ；inf( 7000000002 )≈  21056511.1 , jd ≈0.99957 ,infS(m) = 9870239.59 ,
G(7000000004) = 10031099 ；inf( 7000000004 )≈  10027652.0 , jd ≈0.99966 ,infS(m) = 9870239.59 ,
G(7000000006) = 9873946 ；inf( 7000000006 )≈ 9870584.3  , jd ≈0.99966 ,infS(m) = 9870239.59 ,
G(7000000008) = 19743455 ；inf( 7000000008 )≈  19740479.2 , jd ≈0.99985 ,infS(m) = 9870239.59 ,
G(7000000010) = 13166690 ；inf( 7000000010 )≈  13160319.5 , jd ≈0.99952 ,infS(m) = 9870239.6 ,
G(7000000012) = 10417175 ；inf( 7000000012 )≈  10411151.4 , jd ≈0.99942 ,infS(m) = 9870239.6 ,
G(7000000014) = 24302006 ；inf( 7000000014 )≈  24297245.2 , jd ≈0.99980 ,infS(m) = 9870239.6 ,
G(7000000016) = 10136399 ；inf( 7000000016 )≈  10131501.2 , jd ≈0.99952 ,infS(m) = 9870239.6，
time start =13:55:49  ,time end =13:56:49 ,time use =

计算式：
inf( 7000000006 ) = 1/(1+ .148 )*( 7000000006 /2 -2)*p(m) ≈ 9870584.300000001
inf( 7000000008 ) = 1/(1+ .148 )*( 7000000008 /2 -2)*p(m) ≈ 19740479.2
inf( 7000000010 ) = 1/(1+ .148 )*( 7000000010 /2 -2)*p(m) ≈ 13160319.5
inf( 7000000012 ) = 1/(1+ .148 )*( 7000000012 /2 -2)*p(m) ≈ 10411151.4
inf( 7000000014 ) = 1/(1+ .148 )*( 7000000014 /2 -2)*p(m) ≈ 24297245.2
inf( 7000000016 ) = 1/(1+ .148 )*( 7000000016 /2 -2)*p(m) ≈ 10131501.2

inf( 7900000000 ) = 1/(1+ .148 )*( 7900000000 /2 -2)*p(m) ≈ 14891133.9
inf( 7900000002 ) = 1/(1+ .148 )*( 7900000002 /2 -2)*p(m) ≈ 22050333
inf( 7900000004 ) = 1/(1+ .148 )*( 7900000004 /2 -2)*p(m) ≈ 12027454.3
inf( 7900000006 ) = 1/(1+ .148 )*( 7900000006 /2 -2)*p(m) ≈ 11680584.7
inf( 7900000008 ) = 1/(1+ .148 )*( 7900000008 /2 -2)*p(m) ≈ 22054816.7
inf( 7900000010 ) = 1/(1+ .148 )*( 7900000010 /2 -2)*p(m) ≈ 18248797.1

G(7900000000) = 14883005 ；inf( 7900000000 )≈  14891133.9 , jd≈1.00055,
G(7900000002) = 22036961 ；inf( 7900000002 )≈  22050333 , jd≈1.00061,
G(7900000004) = 12021723 ；inf( 7900000004 )≈  12027454.3 , jd≈1.00048，
G(7900000006) = 11674176 ；inf( 7900000006 )≈  11680584.7 , jd≈1.00055,
G(7900000008) = 22043224 ；inf( 7900000008 )≈  22054816.7 , jd≈1.00053,
G(7900000010) = 18237791 ；inf( 7900000010 )≈  18248797.1 , jd≈1.00060,
time start =14:18:39  ,time end =14:19:47 ,time use =

愚工688 · 发表于 2023-12-8 13:24

  偶数M=2A拆分成两个素数的变量x与A不构成同余关系的数量与连乘式计算值的相对误差（700-1000）：
式中： δ(m)——连乘式计算值对全部素数对数量的相对误差；
      δ1(m)——连乘式计算值对变量x与A不构成同余关系的数量的相对误差;(即根号外的素数对数量）

S( 700 )= 24       S1(m)= 22    S2(m)= 2  Sp(m)≈ 19.8    δ(m)≈-.173  δ1(m)≈-.098
S( 702 )= 31       S1(m)= 29    S2(m)= 2  Sp(m)≈ 27.1    δ(m)≈-.1244 δ1(m)≈-.064
S( 704 )= 18       S1(m)= 16    S2(m)= 2  Sp(m)≈ 13.9    δ(m)≈-.2299 δ1(m)≈-.134
S( 706 )= 19       S1(m)= 17    S2(m)= 2  Sp(m)≈ 12.5    δ(m)≈-.3415 δ1(m)≈-.264
S( 708 )= 24       S1(m)= 22    S2(m)= 2  Sp(m)≈ 25.1    δ(m)≈ .0456 δ1(m)≈ .141
S( 710 )= 16       S1(m)= 15    S2(m)= 1  Sp(m)≈ 16.8    δ(m)≈ .0486 δ1(m)≈ .118
S( 712 )= 17       S1(m)= 15    S2(m)= 2  Sp(m)≈ 12.6    δ(m)≈-.2577 δ1(m)≈-.159
S( 714 )= 37       S1(m)= 34    S2(m)= 3  Sp(m)≈ 32.4    δ(m)≈-.1245 δ1(m)≈-.047
S( 716 )= 14       S1(m)= 13    S2(m)= 1  Sp(m)≈ 12.7    δ(m)≈-.0936 δ1(m)≈-.024
S( 718 )= 15       S1(m)= 14    S2(m)= 1  Sp(m)≈ 12.7    δ(m)≈-.1516 δ1(m)≈-.091
S( 720 )= 39       S1(m)= 37    S2(m)= 2  Sp(m)≈ 34    δ(m)≈-.1275 δ1(m)≈-.08
S( 722 )= 14       S1(m)= 12    S2(m)= 2  Sp(m)≈ 13.5    δ(m)≈-.0322 δ1(m)≈ .129
S( 724 )= 15       S1(m)= 13    S2(m)= 2  Sp(m)≈ 12.8    δ(m)≈-.1445 δ1(m)≈-.013
S( 726 )= 31       S1(m)= 29    S2(m)= 2  Sp(m)≈ 28.6    δ(m)≈-.0776 δ1(m)≈-.014
S( 728 )= 15       S1(m)= 14    S2(m)= 1  Sp(m)≈ 16.9    δ(m)≈ .1261 δ1(m)≈ .207
S( 730 )= 21       S1(m)= 19    S2(m)= 2  Sp(m)≈ 17.3    δ(m)≈-.1785 δ1(m)≈-.092
S( 732 )= 31       S1(m)= 28    S2(m)= 3  Sp(m)≈ 25.9    δ(m)≈-.1629 δ1(m)≈-.073
S( 734 )= 15       S1(m)= 14    S2(m)= 1  Sp(m)≈ 13    δ(m)≈-.1326 δ1(m)≈-.071
S( 736 )= 19       S1(m)= 17    S2(m)= 2  Sp(m)≈ 13.7    δ(m)≈-.2807 δ1(m)≈-.196
S( 738 )= 29       S1(m)= 26    S2(m)= 3  Sp(m)≈ 26.2    δ(m)≈-.0978 δ1(m)≈ .006
S( 740 )= 18       S1(m)= 16    S2(m)= 2  Sp(m)≈ 17.5    δ(m)≈-.0283 δ1(m)≈ .093
S( 742 )= 19       S1(m)= 17    S2(m)= 2  Sp(m)≈ 15.8    δ(m)≈-.1693 δ1(m)≈-.072
S( 744 )= 31       S1(m)= 28    S2(m)= 3  Sp(m)≈ 26.4    δ(m)≈-.1491 δ1(m)≈-.058
S( 746 )= 18       S1(m)= 14    S2(m)= 4  Sp(m)≈ 13.2    δ(m)≈-.2653 δ1(m)≈-.055
S( 748 )= 19       S1(m)= 18    S2(m)= 1  Sp(m)≈ 15.7    δ(m)≈-.1729 δ1(m)≈-.127
S( 750 )= 39       S1(m)= 35    S2(m)= 4  Sp(m)≈ 35.5    δ(m)≈-.0909 δ1(m)≈ .013
S( 752 )= 14       S1(m)= 12    S2(m)= 2  Sp(m)≈ 13.3    δ(m)≈-.0478 δ1(m)≈ .111
S( 754 )= 17       S1(m)= 15    S2(m)= 2  Sp(m)≈ 14.6    δ(m)≈-.1422 δ1(m)≈-.028
S( 756 )= 35       S1(m)= 31    S2(m)= 4  Sp(m)≈ 32.2    δ(m)≈-.081  δ1(m)≈ .038
S( 758 )= 15       S1(m)= 13    S2(m)= 2  Sp(m)≈ 13.4    δ(m)≈-.1041 δ1(m)≈ .034
S( 760 )= 21       S1(m)= 19    S2(m)= 2  Sp(m)≈ 19    δ(m)≈-.0942 δ1(m)≈ .001
S( 762 )= 30       S1(m)= 26    S2(m)= 4  Sp(m)≈ 27    δ(m)≈-.0994 δ1(m)≈ .039
S( 764 )= 17       S1(m)= 14    S2(m)= 3  Sp(m)≈ 13.5    δ(m)≈-.2032 δ1(m)≈-.032
S( 766 )= 17       S1(m)= 15    S2(m)= 2  Sp(m)≈ 13.6    δ(m)≈-.2011 δ1(m)≈-.095
S( 768 )= 31       S1(m)= 28    S2(m)= 3  Sp(m)≈ 27.2    δ(m)≈-.1215 δ1(m)≈-.027
S( 770 )= 26       S1(m)= 24    S2(m)= 2  Sp(m)≈ 24.3    δ(m)≈-.0665 δ1(m)≈ .011
S( 772 )= 18       S1(m)= 16    S2(m)= 2  Sp(m)≈ 13.7    δ(m)≈-.2396 δ1(m)≈-.145
S( 774 )= 32       S1(m)= 28    S2(m)= 4  Sp(m)≈ 27.4    δ(m)≈-.1423 δ1(m)≈-.02
S( 776 )= 16       S1(m)= 13    S2(m)= 3  Sp(m)≈ 13.8    δ(m)≈-.1401 δ1(m)≈ .058
S( 778 )= 15       S1(m)= 13    S2(m)= 2  Sp(m)≈ 13.8    δ(m)≈-.0804 δ1(m)≈ .061
S( 780 )= 44       S1(m)= 40    S2(m)= 4  Sp(m)≈ 40.2    δ(m)≈-.0856 δ1(m)≈ .006
S( 782 )= 14       S1(m)= 13    S2(m)= 1  Sp(m)≈ 15.5    δ(m)≈ .1068 δ1(m)≈ .192
S( 784 )= 18       S1(m)= 16    S2(m)= 2  Sp(m)≈ 16.7    δ(m)≈-.0732 δ1(m)≈ .043
S( 786 )= 30       S1(m)= 28    S2(m)= 2  Sp(m)≈ 27.9    δ(m)≈-.0709 δ1(m)≈-.004
S( 788 )= 15       S1(m)= 14    S2(m)= 1  Sp(m)≈ 14    δ(m)≈-.0685 δ1(m)≈-.002
S( 790 )= 22       S1(m)= 20    S2(m)= 2  Sp(m)≈ 18.7    δ(m)≈-.151  δ1(m)≈-.066
S( 792 )= 34       S1(m)= 31    S2(m)= 3  Sp(m)≈ 31.2    δ(m)≈-.0821 δ1(m)≈ .007
S( 794 )= 17       S1(m)= 16    S2(m)= 1  Sp(m)≈ 14.1    δ(m)≈-.1718 δ1(m)≈-.12
S( 796 )= 14       S1(m)= 13    S2(m)= 1  Sp(m)≈ 14.1    δ(m)≈ .0082 δ1(m)≈ .086
S( 798 )= 38       S1(m)= 37    S2(m)= 1  Sp(m)≈ 36    δ(m)≈-.0537 δ1(m)≈-.028
S( 800 )= 21       S1(m)= 19    S2(m)= 2  Sp(m)≈ 18.9    δ(m)≈-.0993 δ1(m)≈-.004
S( 802 )= 16       S1(m)= 15    S2(m)= 1  Sp(m)≈ 14.2    δ(m)≈-.1111 δ1(m)≈-.052
S( 804 )= 32       S1(m)= 30    S2(m)= 2  Sp(m)≈ 28.5    δ(m)≈-.1089 δ1(m)≈-.049
S( 806 )= 16       S1(m)= 15    S2(m)= 1  Sp(m)≈ 15.6    δ(m)≈-.0254 δ1(m)≈ .04
S( 808 )= 14       S1(m)= 13    S2(m)= 1  Sp(m)≈ 14.3    δ(m)≈ .0235 δ1(m)≈ .102
S( 810 )= 39       S1(m)= 37    S2(m)= 2  Sp(m)≈ 38.3    δ(m)≈-.0178 δ1(m)≈ .035
S( 812 )= 18       S1(m)= 17    S2(m)= 1  Sp(m)≈ 17.3    δ(m)≈-.04 δ1(m)≈ .017
S( 814 )= 20       S1(m)= 17    S2(m)= 3  Sp(m)≈ 16    δ(m)≈-.198  δ1(m)≈-.056
S( 816 )= 34       S1(m)= 31    S2(m)= 3  Sp(m)≈ 30.9    δ(m)≈-.092  δ1(m)≈-.004
S( 818 )= 17       S1(m)= 16    S2(m)= 1  Sp(m)≈ 14.5    δ(m)≈-.1466 δ1(m)≈-.093
S( 820 )= 20       S1(m)= 18    S2(m)= 2  Sp(m)≈ 19.4    δ(m)≈-.0305 δ1(m)≈ .077
S( 822 )= 29       S1(m)= 27    S2(m)= 2  Sp(m)≈ 29.2    δ(m)≈ .0054 δ1(m)≈ .08
S( 824 )= 16       S1(m)= 14    S2(m)= 2  Sp(m)≈ 14.6    δ(m)≈-.0866 δ1(m)≈ .044
S( 826 )= 21       S1(m)= 18    S2(m)= 3  Sp(m)≈ 17.6    δ(m)≈-.1628 δ1(m)≈-.023
S( 828 )= 34       S1(m)= 30    S2(m)= 4  Sp(m)≈ 30.8    δ(m)≈-.095  δ1(m)≈ .026
S( 830 )= 22       S1(m)= 19    S2(m)= 3  Sp(m)≈ 19.6    δ(m)≈-.1078 δ1(m)≈ .033
S( 832 )= 22       S1(m)= 18    S2(m)= 4  Sp(m)≈ 16.1    δ(m)≈-.2682 δ1(m)≈-.106
S( 834 )= 33       S1(m)= 28    S2(m)= 5  Sp(m)≈ 29.6    δ(m)≈-.1035 δ1(m)≈ .057
S( 836 )= 18       S1(m)= 16    S2(m)= 2  Sp(m)≈ 17.4    δ(m)≈-.0308 δ1(m)≈ .09
S( 838 )= 17       S1(m)= 15    S2(m)= 2  Sp(m)≈ 14.9    δ(m)≈-.1256 δ1(m)≈-.009
S( 840 )= 51       S1(m)= 47    S2(m)= 4  Sp(m)≈ 47.7    δ(m)≈-.0651 δ1(m)≈ .014
S( 842 )= 18       S1(m)= 15    S2(m)= 3  Sp(m)≈ 14.9    δ(m)≈-.1703 δ1(m)≈-.004
S( 844 )= 17       S1(m)= 14    S2(m)= 3  Sp(m)≈ 13.9    δ(m)≈-.1801 δ1(m)≈-.004
S( 846 )= 32       S1(m)= 28    S2(m)= 4  Sp(m)≈ 27.9    δ(m)≈-.1268 δ1(m)≈-.002
S( 848 )= 15       S1(m)= 14    S2(m)= 1  Sp(m)≈ 14    δ(m)≈-.0663 δ1(m)≈ 0
S( 850 )= 25       S1(m)= 22    S2(m)= 3  Sp(m)≈ 20    δ(m)≈-.2014 δ1(m)≈-.092
S( 852 )= 31       S1(m)= 28    S2(m)= 3  Sp(m)≈ 28.1    δ(m)≈-.0922 δ1(m)≈ .005
S( 854 )= 20       S1(m)= 20    S2(m)= 0  Sp(m)≈ 16.9    δ(m)≈-.1537 δ1(m)≈-.154
S( 856 )= 19       S1(m)= 16    S2(m)= 3  Sp(m)≈ 14.1    δ(m)≈-.2559 δ1(m)≈-.116
S( 858 )= 39       S1(m)= 36    S2(m)= 3  Sp(m)≈ 34.4    δ(m)≈-.1191 δ1(m)≈-.046
S( 860 )= 18       S1(m)= 16    S2(m)= 2  Sp(m)≈ 18.9    δ(m)≈ .0521 δ1(m)≈ .184
S( 862 )= 17       S1(m)= 14    S2(m)= 3  Sp(m)≈ 14.2    δ(m)≈-.1625 δ1(m)≈ .017
S( 864 )= 33       S1(m)= 30    S2(m)= 3  Sp(m)≈ 28.5    δ(m)≈-.1351 δ1(m)≈-.049
S( 866 )= 17       S1(m)= 14    S2(m)= 3  Sp(m)≈ 14.3    δ(m)≈-.1586 δ1(m)≈ .022
S( 868 )= 21       S1(m)= 18    S2(m)= 3  Sp(m)≈ 17.2    δ(m)≈-.1808 δ1(m)≈-.044
S( 870 )= 46       S1(m)= 42    S2(m)= 4  Sp(m)≈ 39.7    δ(m)≈-.1361 δ1(m)≈-.054
S( 872 )= 18       S1(m)= 16    S2(m)= 2  Sp(m)≈ 14.4    δ(m)≈-.1998 δ1(m)≈-.1
S( 874 )= 19       S1(m)= 17    S2(m)= 2  Sp(m)≈ 16    δ(m)≈-.1572 δ1(m)≈-.058
S( 876 )= 36       S1(m)= 32    S2(m)= 4  Sp(m)≈ 28.9    δ(m)≈-.1961 δ1(m)≈-.096
S( 878 )= 14       S1(m)= 13    S2(m)= 1  Sp(m)≈ 14.5    δ(m)≈ .0359 δ1(m)≈ .116
S( 880 )= 25       S1(m)= 22    S2(m)= 3  Sp(m)≈ 21.5    δ(m)≈-.1386 δ1(m)≈-.021
S( 882 )= 39       S1(m)= 35    S2(m)= 4  Sp(m)≈ 35    δ(m)≈-.1034 δ1(m)≈-.001
S( 884 )= 21       S1(m)= 19    S2(m)= 2  Sp(m)≈ 17    δ(m)≈-.1909 δ1(m)≈-.106
S( 886 )= 18       S1(m)= 14    S2(m)= 4  Sp(m)≈ 14.6    δ(m)≈-.1869 δ1(m)≈ .045
S( 888 )= 37       S1(m)= 33    S2(m)= 4  Sp(m)≈ 29.3    δ(m)≈-.2071 δ1(m)≈-.111
S( 890 )= 23       S1(m)= 20    S2(m)= 3  Sp(m)≈ 19.6    δ(m)≈-.1477 δ1(m)≈-.02
S( 892 )= 19       S1(m)= 16    S2(m)= 3  Sp(m)≈ 14.7    δ(m)≈-.2245 δ1(m)≈-.079
S( 894 )= 34       S1(m)= 30    S2(m)= 4  Sp(m)≈ 29.5    δ(m)≈-.1313 δ1(m)≈-.015
S( 896 )= 20       S1(m)= 18    S2(m)= 2  Sp(m)≈ 17.8    δ(m)≈-.1119 δ1(m)≈-.013
S( 898 )= 19       S1(m)= 17    S2(m)= 2  Sp(m)≈ 14.8    δ(m)≈-.2192 δ1(m)≈-.127
S( 900 )= 48       S1(m)= 44    S2(m)= 4  Sp(m)≈ 39.6    δ(m)≈-.174  δ1(m)≈-.099
S( 902 )= 15       S1(m)= 14    S2(m)= 1  Sp(m)≈ 16.6    δ(m)≈ .1038 δ1(m)≈ .183
S( 904 )= 17       S1(m)= 15    S2(m)= 2  Sp(m)≈ 14.9    δ(m)≈-.1215 δ1(m)≈-.004
S( 906 )= 34       S1(m)= 31    S2(m)= 3  Sp(m)≈ 29.9    δ(m)≈-.1196 δ1(m)≈-.034
S( 908 )= 15       S1(m)= 15    S2(m)= 0  Sp(m)≈ 15    δ(m)≈ 0    δ1(m)≈ 0
S( 910 )= 31       S1(m)= 28    S2(m)= 3  Sp(m)≈ 26.2    δ(m)≈-.1535 δ1(m)≈-.063
S( 912 )= 31       S1(m)= 29    S2(m)= 2  Sp(m)≈ 31.9    δ(m)≈ .0292 δ1(m)≈ .1
S( 914 )= 20       S1(m)= 18    S2(m)= 2  Sp(m)≈ 15.1    δ(m)≈-.245  δ1(m)≈-.161
S( 916 )= 18       S1(m)= 16    S2(m)= 2  Sp(m)≈ 15.1    δ(m)≈-.1593 δ1(m)≈-.054
S( 918 )= 35       S1(m)= 33    S2(m)= 2  Sp(m)≈ 32.4    δ(m)≈-.0756 δ1(m)≈-.02
S( 920 )= 23       S1(m)= 22    S2(m)= 1  Sp(m)≈ 21.2    δ(m)≈-.0769 δ1(m)≈-.035
S( 922 )= 20       S1(m)= 18    S2(m)= 2  Sp(m)≈ 15.2    δ(m)≈-.2384 δ1(m)≈-.154
S( 924 )= 47       S1(m)= 44    S2(m)= 3  Sp(m)≈ 40.7    δ(m)≈-.1338 δ1(m)≈-.075
S( 926 )= 18       S1(m)= 16    S2(m)= 2  Sp(m)≈ 15.3    δ(m)≈-.15 δ1(m)≈-.044
S( 928 )= 18       S1(m)= 17    S2(m)= 1  Sp(m)≈ 15.9    δ(m)≈-.1167 δ1(m)≈-.065
S( 930 )= 43       S1(m)= 40    S2(m)= 3  Sp(m)≈ 41    δ(m)≈-.0471 δ1(m)≈ .024
S( 932 )= 17       S1(m)= 15    S2(m)= 2  Sp(m)≈ 15.4    δ(m)≈-.0942 δ1(m)≈ .027
S( 934 )= 20       S1(m)= 18    S2(m)= 2  Sp(m)≈ 15.4    δ(m)≈-.2284 δ1(m)≈-.143
S( 936 )= 36       S1(m)= 33    S2(m)= 3  Sp(m)≈ 33.7    δ(m)≈-.0627 δ1(m)≈ .022
S( 938 )= 18       S1(m)= 17    S2(m)= 1  Sp(m)≈ 18.6    δ(m)≈ .0332 δ1(m)≈ .094
S( 940 )= 24       S1(m)= 21    S2(m)= 3  Sp(m)≈ 20.7    δ(m)≈-.1371 δ1(m)≈-.014
S( 942 )= 34       S1(m)= 31    S2(m)= 3  Sp(m)≈ 31.1    δ(m)≈-.0844 δ1(m)≈ .004
S( 944 )= 18       S1(m)= 16    S2(m)= 2  Sp(m)≈ 15.6    δ(m)≈-.1335 δ1(m)≈-.025
S( 946 )= 20       S1(m)= 18    S2(m)= 2  Sp(m)≈ 17.4    δ(m)≈-.1316 δ1(m)≈-.035
S( 948 )= 33       S1(m)= 29    S2(m)= 4  Sp(m)≈ 31.3    δ(m)≈-.0507 δ1(m)≈ .08
S( 950 )= 25       S1(m)= 23    S2(m)= 2  Sp(m)≈ 22.2    δ(m)≈-.1136 δ1(m)≈-.036
S( 952 )= 23       S1(m)= 20    S2(m)= 3  Sp(m)≈ 20.1    δ(m)≈-.1246 δ1(m)≈ .007
S( 954 )= 37       S1(m)= 34    S2(m)= 3  Sp(m)≈ 31.5    δ(m)≈-.1479 δ1(m)≈-.073
S( 956 )= 19       S1(m)= 17    S2(m)= 2  Sp(m)≈ 15.8    δ(m)≈-.1686 δ1(m)≈-.071
S( 958 )= 22       S1(m)= 18    S2(m)= 4  Sp(m)≈ 15.8    δ(m)≈-.2804 δ1(m)≈-.121
S( 960 )= 45       S1(m)= 41    S2(m)= 4  Sp(m)≈ 42.3    δ(m)≈-.06 δ1(m)≈ .032
S( 962 )= 16       S1(m)= 16    S2(m)= 0  Sp(m)≈ 17.3    δ(m)≈ .0839 δ1(m)≈ .084
S( 964 )= 18       S1(m)= 15    S2(m)= 3  Sp(m)≈ 14.9    δ(m)≈-.1721 δ1(m)≈-.007
S( 966 )= 45       S1(m)= 42    S2(m)= 3  Sp(m)≈ 37.5    δ(m)≈-.1656 δ1(m)≈-.106
S( 968 )= 17       S1(m)= 16    S2(m)= 1  Sp(m)≈ 16.6    δ(m)≈-.022  δ1(m)≈ .039
S( 970 )= 27       S1(m)= 23    S2(m)= 4  Sp(m)≈ 20    δ(m)≈-.2595 δ1(m)≈-.131
S( 972 )= 32       S1(m)= 29    S2(m)= 3  Sp(m)≈ 30.1    δ(m)≈-.0609 δ1(m)≈ .036
S( 974 )= 17       S1(m)= 15    S2(m)= 2  Sp(m)≈ 15.1    δ(m)≈-.1143 δ1(m)≈ .004
S( 976 )= 19       S1(m)= 16    S2(m)= 3  Sp(m)≈ 15.1    δ(m)≈-.2059 δ1(m)≈-.057
S( 978 )= 35       S1(m)= 32    S2(m)= 3  Sp(m)≈ 30.2    δ(m)≈-.136  δ1(m)≈-.055
S( 980 )= 26       S1(m)= 24    S2(m)= 2  Sp(m)≈ 24.2    δ(m)≈-.0677 δ1(m)≈ .01
S( 982 )= 17       S1(m)= 14    S2(m)= 3  Sp(m)≈ 15.2    δ(m)≈-.107  δ1(m)≈ .084
S( 984 )= 39       S1(m)= 35    S2(m)= 4  Sp(m)≈ 30.4    δ(m)≈-.2199 δ1(m)≈-.131
S( 986 )= 20       S1(m)= 18    S2(m)= 2  Sp(m)≈ 16.9    δ(m)≈-.1569 δ1(m)≈-.063
S( 988 )= 23       S1(m)= 20    S2(m)= 3  Sp(m)≈ 17.6    δ(m)≈-.2329 δ1(m)≈-.118
S( 990 )= 52       S1(m)= 48    S2(m)= 4  Sp(m)≈ 45.3    δ(m)≈-.1279 δ1(m)≈-.055
S( 992 )= 13       S1(m)= 13    S2(m)= 0  Sp(m)≈ 15.9    δ(m)≈ .2204 δ1(m)≈ .22
S( 994 )= 25       S1(m)= 21    S2(m)= 4  Sp(m)≈ 18.4    δ(m)≈-.2624 δ1(m)≈-.122
S( 996 )= 37       S1(m)= 33    S2(m)= 4  Sp(m)≈ 30.8    δ(m)≈-.1676 δ1(m)≈-.067
S( 998 )= 17       S1(m)= 15    S2(m)= 2  Sp(m)≈ 15.4    δ(m)≈-.0924 δ1(m)≈ .029
S( 1000 )= 28    S1(m)= 24    S2(m)= 4  Sp(m)≈ 20.6    δ(m)≈-.2638 δ1(m)≈-.141

愚工688 · 发表于 2023-12-8 13:30

愚工688 发表于 2023-12-8 05:24
偶数M=2A拆分成两个素数的变量x与A不构成同余关系的数量与连乘式计算值的相对误差（700-1000）：
式中： ...

偶数M=2A拆分成两个素数的变量x与A不构成同余关系的数量与连乘式计算值的相对误差（1002-2000）：
式中： δ(m)——连乘式计算值对全部素数对数量的相对误差；
          δ1(m)——连乘式计算值对变量x与A不构成同余关系的数量的相对误差;(即根号外的素数对数量）

S( 1002 )= 36    S1(m)= 32    S2(m)= 4  Sp(m)≈ 31    δ(m)≈-.1393 δ1(m)≈-.032
S( 1004 )= 18    S1(m)= 16    S2(m)= 2  Sp(m)≈ 15.5    δ(m)≈-.1376 δ1(m)≈-.03
S( 1006 )= 18    S1(m)= 16    S2(m)= 2  Sp(m)≈ 15.6    δ(m)≈-.1359 δ1(m)≈-.028
S( 1008 )= 42    S1(m)= 39    S2(m)= 3  Sp(m)≈ 37.4    δ(m)≈-.1094 δ1(m)≈-.041
S( 1010 )= 25    S1(m)= 23    S2(m)= 2  Sp(m)≈ 20.8    δ(m)≈-.1671 δ1(m)≈-.095
S( 1012 )= 23    S1(m)= 21    S2(m)= 2  Sp(m)≈ 18.2    δ(m)≈-.2081 δ1(m)≈-.133
S( 1014 )= 39    S1(m)= 35    S2(m)= 4  Sp(m)≈ 34.2    δ(m)≈-.1229 δ1(m)≈-.023
S( 1016 )= 18    S1(m)= 15    S2(m)= 3  Sp(m)≈ 15.7    δ(m)≈-.1273 δ1(m)≈ .047
S( 1018 )= 20    S1(m)= 19    S2(m)= 1  Sp(m)≈ 15.7    δ(m)≈-.213 δ1(m)≈-.172
S( 1020 )= 51    S1(m)= 47    S2(m)= 4  Sp(m)≈ 44.9    δ(m)≈-.1204 δ1(m)≈-.046
S( 1022 )= 18    S1(m)= 15    S2(m)= 3  Sp(m)≈ 19    δ(m)≈ .0535 δ1(m)≈ .264
S( 1024 )= 22    S1(m)= 19    S2(m)= 3  Sp(m)≈ 15.8    δ(m)≈-.2803 δ1(m)≈-.167
S( 1026 )= 42    S1(m)= 37    S2(m)= 5  Sp(m)≈ 33.6    δ(m)≈-.2001 δ1(m)≈-.092
S( 1028 )= 18    S1(m)= 15    S2(m)= 3  Sp(m)≈ 15.9    δ(m)≈-.1169 δ1(m)≈ .06
S( 1030 )= 25    S1(m)= 23    S2(m)= 2  Sp(m)≈ 21.2    δ(m)≈-.1506 δ1(m)≈-.077
S( 1032 )= 36    S1(m)= 32    S2(m)= 4  Sp(m)≈ 31.9    δ(m)≈-.1135 δ1(m)≈-.003
S( 1034 )= 21    S1(m)= 19    S2(m)= 2  Sp(m)≈ 17.8    δ(m)≈-.154 δ1(m)≈-.065
S( 1036 )= 27    S1(m)= 23    S2(m)= 4  Sp(m)≈ 19.2    δ(m)≈-.288 δ1(m)≈-.164
S( 1038 )= 40    S1(m)= 35    S2(m)= 5  Sp(m)≈ 32.1    δ(m)≈-.1975 δ1(m)≈-.083
S( 1040 )= 26    S1(m)= 23    S2(m)= 3  Sp(m)≈ 23.4    δ(m)≈-.1003 δ1(m)≈ .017
S( 1042 )= 22    S1(m)= 18    S2(m)= 4  Sp(m)≈ 16.1    δ(m)≈-.2676 δ1(m)≈-.105
S( 1044 )= 39    S1(m)= 34    S2(m)= 5  Sp(m)≈ 33.5    δ(m)≈-.1415 δ1(m)≈-.015
S( 1046 )= 19    S1(m)= 17    S2(m)= 2  Sp(m)≈ 16.2    δ(m)≈-.1487 δ1(m)≈-.049
S( 1048 )= 19    S1(m)= 17    S2(m)= 2  Sp(m)≈ 16.2    δ(m)≈-.1471 δ1(m)≈-.047
S( 1050 )= 57    S1(m)= 52    S2(m)= 5  Sp(m)≈ 52    δ(m)≈-.0885 δ1(m)≈-.001
S( 1052 )= 18    S1(m)= 14    S2(m)= 4  Sp(m)≈ 16.3    δ(m)≈-.0962 δ1(m)≈ .162
S( 1054 )= 24    S1(m)= 21    S2(m)= 3  Sp(m)≈ 18    δ(m)≈-.2506 δ1(m)≈-.144
S( 1056 )= 44    S1(m)= 40    S2(m)= 4  Sp(m)≈ 36.3    δ(m)≈-.1752 δ1(m)≈-.093
S( 1058 )= 19    S1(m)= 17    S2(m)= 2  Sp(m)≈ 17.1    δ(m)≈-.0979 δ1(m)≈ .008
S( 1060 )= 27    S1(m)= 25    S2(m)= 2  Sp(m)≈ 21.9    δ(m)≈-.1905 δ1(m)≈-.126
S( 1062 )= 37    S1(m)= 32    S2(m)= 5  Sp(m)≈ 32.8    δ(m)≈-.1123 δ1(m)≈ .026
S( 1064 )= 24    S1(m)= 21    S2(m)= 3  Sp(m)≈ 20.9    δ(m)≈-.1289 δ1(m)≈-.004
S( 1066 )= 24    S1(m)= 21    S2(m)= 3  Sp(m)≈ 18    δ(m)≈-.2507 δ1(m)≈-.144
S( 1068 )= 39    S1(m)= 34    S2(m)= 5  Sp(m)≈ 33    δ(m)≈-.153 δ1(m)≈-.028
S( 1070 )= 25    S1(m)= 22    S2(m)= 3  Sp(m)≈ 22.1    δ(m)≈-.1175 δ1(m)≈ .003
S( 1072 )= 21    S1(m)= 18    S2(m)= 3  Sp(m)≈ 16.6    δ(m)≈-.2106 δ1(m)≈-.079
S( 1074 )= 40    S1(m)= 36    S2(m)= 4  Sp(m)≈ 33.2    δ(m)≈-.1695 δ1(m)≈-.077
S( 1076 )= 20    S1(m)= 18    S2(m)= 2  Sp(m)≈ 16.6    δ(m)≈-.168 δ1(m)≈-.076
S( 1078 )= 27    S1(m)= 25    S2(m)= 2  Sp(m)≈ 22.2    δ(m)≈-.1767 δ1(m)≈-.111
S( 1080 )= 54    S1(m)= 49    S2(m)= 5  Sp(m)≈ 44.5    δ(m)≈-.1752 δ1(m)≈-.091
S( 1082 )= 20    S1(m)= 17    S2(m)= 3  Sp(m)≈ 16.7    δ(m)≈-.1633 δ1(m)≈-.016
S( 1084 )= 21    S1(m)= 20    S2(m)= 1  Sp(m)≈ 16.8    δ(m)≈-.2017 δ1(m)≈-.162
S( 1086 )= 39    S1(m)= 37    S2(m)= 2  Sp(m)≈ 33.6    δ(m)≈-.1387 δ1(m)≈-.092
S( 1088 )= 18    S1(m)= 17    S2(m)= 1  Sp(m)≈ 17.9    δ(m)≈-.0029 δ1(m)≈ .056
S( 1090 )= 26    S1(m)= 24    S2(m)= 2  Sp(m)≈ 22.5    δ(m)≈-.1355 δ1(m)≈-.063
S( 1092 )= 48    S1(m)= 44    S2(m)= 4  Sp(m)≈ 44.2    δ(m)≈-.0788 δ1(m)≈ .005
S( 1094 )= 23    S1(m)= 20    S2(m)= 3  Sp(m)≈ 16.9    δ(m)≈-.2644 δ1(m)≈-.154
S( 1096 )= 18    S1(m)= 16    S2(m)= 2  Sp(m)≈ 17    δ(m)≈-.0583 δ1(m)≈ .059
S( 1098 )= 40    S1(m)= 36    S2(m)= 4  Sp(m)≈ 34    δ(m)≈-.1509 δ1(m)≈-.057
S( 1100 )= 28    S1(m)= 24    S2(m)= 4  Sp(m)≈ 25.2    δ(m)≈-.0998 δ1(m)≈ .05
S( 1102 )= 24    S1(m)= 22    S2(m)= 2  Sp(m)≈ 18.7    δ(m)≈-.2202 δ1(m)≈-.149
S( 1104 )= 44    S1(m)= 40    S2(m)= 4  Sp(m)≈ 35.8    δ(m)≈-.1869 δ1(m)≈-.106
S( 1106 )= 25    S1(m)= 22    S2(m)= 3  Sp(m)≈ 20.5    δ(m)≈-.1789 δ1(m)≈-.067
S( 1108 )= 25    S1(m)= 22    S2(m)= 3  Sp(m)≈ 17.1    δ(m)≈-.3145 δ1(m)≈-.221
S( 1110 )= 54    S1(m)= 49    S2(m)= 5  Sp(m)≈ 45.8    δ(m)≈-.1522 δ1(m)≈-.066
S( 1112 )= 16    S1(m)= 14    S2(m)= 2  Sp(m)≈ 17.2    δ(m)≈ .075 δ1(m)≈ .229
S( 1114 )= 23    S1(m)= 19    S2(m)= 4  Sp(m)≈ 17.2    δ(m)≈-.2509 δ1(m)≈-.093
S( 1116 )= 41    S1(m)= 36    S2(m)= 5  Sp(m)≈ 35.7    δ(m)≈-.1289 δ1(m)≈-.008
S( 1118 )= 22    S1(m)= 21    S2(m)= 1  Sp(m)≈ 18.9    δ(m)≈-.1425 δ1(m)≈-.102
S( 1120 )= 34    S1(m)= 29    S2(m)= 5  Sp(m)≈ 27.7    δ(m)≈-.1848 δ1(m)≈-.044
S( 1122 )= 47    S1(m)= 42    S2(m)= 5  Sp(m)≈ 41.1    δ(m)≈-.1247 δ1(m)≈-.021
S( 1124 )= 19    S1(m)= 17    S2(m)= 2  Sp(m)≈ 17.4    δ(m)≈-.085 δ1(m)≈ .023
S( 1126 )= 23    S1(m)= 19    S2(m)= 4  Sp(m)≈ 17.4    δ(m)≈-.2428 δ1(m)≈-.083
S( 1128 )= 39    S1(m)= 35    S2(m)= 4  Sp(m)≈ 34.9    δ(m)≈-.1052 δ1(m)≈-.003
S( 1130 )= 26    S1(m)= 24    S2(m)= 2  Sp(m)≈ 23.3    δ(m)≈-.1037 δ1(m)≈-.029
S( 1132 )= 22    S1(m)= 19    S2(m)= 3  Sp(m)≈ 17.5    δ(m)≈-.2041 δ1(m)≈-.078
S( 1134 )= 49    S1(m)= 45    S2(m)= 4  Sp(m)≈ 42.1    δ(m)≈-.1409 δ1(m)≈-.064
S( 1136 )= 23    S1(m)= 20    S2(m)= 3  Sp(m)≈ 17.6    δ(m)≈-.236 δ1(m)≈-.121
S( 1138 )= 20    S1(m)= 19    S2(m)= 1  Sp(m)≈ 17.6    δ(m)≈-.1199 δ1(m)≈-.074
S( 1140 )= 58    S1(m)= 54    S2(m)= 4  Sp(m)≈ 49.8    δ(m)≈-.1416 δ1(m)≈-.078
S( 1142 )= 18    S1(m)= 16    S2(m)= 2  Sp(m)≈ 17.7    δ(m)≈-.0186 δ1(m)≈ .104
S( 1144 )= 24    S1(m)= 24    S2(m)= 0  Sp(m)≈ 21.4    δ(m)≈-.1063 δ1(m)≈-.106
S( 1146 )= 38    S1(m)= 35    S2(m)= 3  Sp(m)≈ 35.5    δ(m)≈-.067 δ1(m)≈ .013
S( 1148 )= 26    S1(m)= 24    S2(m)= 2  Sp(m)≈ 21.3    δ(m)≈-.1804 δ1(m)≈-.112
S( 1150 )= 27    S1(m)= 27    S2(m)= 0  Sp(m)≈ 24.8    δ(m)≈-.0797 δ1(m)≈-.08
S( 1152 )= 36    S1(m)= 34    S2(m)= 2  Sp(m)≈ 35.6    δ(m)≈-.01    δ1(m)≈ .048
S( 1154 )= 19    S1(m)= 17    S2(m)= 2  Sp(m)≈ 17.9    δ(m)≈-.0605 δ1(m)≈ .05
S( 1156 )= 22    S1(m)= 20    S2(m)= 2  Sp(m)≈ 19.1    δ(m)≈-.133 δ1(m)≈-.046
S( 1158 )= 42    S1(m)= 39    S2(m)= 3  Sp(m)≈ 35.8    δ(m)≈-.147 δ1(m)≈-.081
S( 1160 )= 29    S1(m)= 27    S2(m)= 2  Sp(m)≈ 24.8    δ(m)≈-.1444 δ1(m)≈-.081
S( 1162 )= 25    S1(m)= 24    S2(m)= 1  Sp(m)≈ 21.6    δ(m)≈-.1372 δ1(m)≈-.101
S( 1164 )= 43    S1(m)= 41    S2(m)= 2  Sp(m)≈ 36    δ(m)≈-.1625 δ1(m)≈-.122
S( 1166 )= 24    S1(m)= 22    S2(m)= 2  Sp(m)≈ 20    δ(m)≈-.1649 δ1(m)≈-.089
S( 1168 )= 22    S1(m)= 20    S2(m)= 2  Sp(m)≈ 18.1    δ(m)≈-.1787 δ1(m)≈-.097
S( 1170 )= 58    S1(m)= 55    S2(m)= 3  Sp(m)≈ 52.7    δ(m)≈-.0922 δ1(m)≈-.043
S( 1172 )= 18    S1(m)= 17    S2(m)= 1  Sp(m)≈ 18.1    δ(m)≈ .0073 δ1(m)≈ .067
S( 1174 )= 22    S1(m)= 19    S2(m)= 3  Sp(m)≈ 18.2    δ(m)≈-.1745 δ1(m)≈-.044
S( 1176 )= 49    S1(m)= 46    S2(m)= 3  Sp(m)≈ 43.7    δ(m)≈-.1089 δ1(m)≈-.051
S( 1178 )= 19    S1(m)= 18    S2(m)= 1  Sp(m)≈ 20    δ(m)≈ .0506 δ1(m)≈ .109
S( 1180 )= 26    S1(m)= 24    S2(m)= 2  Sp(m)≈ 24.3    δ(m)≈-.0639 δ1(m)≈ .014
S( 1182 )= 40    S1(m)= 36    S2(m)= 4  Sp(m)≈ 36.6    δ(m)≈-.0857 δ1(m)≈ .016
S( 1184 )= 20    S1(m)= 17    S2(m)= 3  Sp(m)≈ 18.3    δ(m)≈-.0842 δ1(m)≈ .077
S( 1186 )= 20    S1(m)= 18    S2(m)= 2  Sp(m)≈ 18.3    δ(m)≈-.0826 δ1(m)≈ .019
S( 1188 )= 43    S1(m)= 41    S2(m)= 2  Sp(m)≈ 40.8    δ(m)≈-.0502 δ1(m)≈-.004
S( 1190 )= 33    S1(m)= 31    S2(m)= 2  Sp(m)≈ 31.4    δ(m)≈-.0479 δ1(m)≈ .014
S( 1192 )= 23    S1(m)= 20    S2(m)= 3  Sp(m)≈ 18.4    δ(m)≈-.1982 δ1(m)≈-.078
S( 1194 )= 45    S1(m)= 41    S2(m)= 4  Sp(m)≈ 36.9    δ(m)≈-.179 δ1(m)≈-.099
S( 1196 )= 24    S1(m)= 23    S2(m)= 1  Sp(m)≈ 21.1    δ(m)≈-.1189 δ1(m)≈-.081
S( 1198 )= 24    S1(m)= 21    S2(m)= 3  Sp(m)≈ 18.5    δ(m)≈-.2277 δ1(m)≈-.117
S( 1200 )= 54    S1(m)= 50    S2(m)= 4  Sp(m)≈ 49.5    δ(m)≈-.0832 δ1(m)≈-.01

重生888@ · 发表于 2023-12-9 16:11

能把“不同余”的必然性推导出来，才有前途！计算数据再多，也不能起决定性作用。

愚工688 · 发表于 2023-12-9 16:28

愚工688 发表于 2023-12-8 05:30
偶数M=2A拆分成两个素数的变量x与A不构成同余关系的数量与连乘式计算值的相对误差（1002-2000）：
式中 ...

白新岭：愚工688始终如一！  发表于 2023-12-8 10:52
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其实在网络上，真正涉及哥德巴赫猜想“1+1”的帖子很少，涉及具体的“1+1”的素数对的帖子，也许我的【变量x与偶数半值A不构成同余关系】是唯一描述“1+1”的数学原理的帖子。

大部分网友是计算能够产生的素数对的数量，当然多数人的计算值的精度都是可以的，基本上计算值的精度都在80%以上，很少有精度低于50%的。

有些人总是说，哥德巴赫猜想的证明只要有一个素数对就可以了，但是只总结出有一个素数对是没有办法得到素数对数量变化的规律性的，有不能得出自己的计算式的有效性的结论。

而【变量x与偶数半值A不构成同余关系】构成偶数2A的哥德巴赫猜想“1+1”的数学原理，则是最容易证明的原理，因为自然数中的数除以任意素数的余数是呈现周期性循环变化的，保障了满足不能被√M内的素数整除的变量的必然存在，也就是2A=(A-x)+(A+x)必然能够成为素数对。

以今天日期的十倍为随机偶数计算其素数对数量的下界：

G(202312090) = 551851 ；inf( 202312090 )≈  548322 , jd ≈0.9936 , k(m)= 1.35293
G(202312092) = 816334 ；inf( 202312092 )≈  810570.8 , jd ≈0.9929  , k(m)= 2
G(202312094) = 428307 ；inf( 202312094 )≈  424584.7 , jd ≈0.9913  , k(m)= 1.04762
G(202312096) = 489947 ；inf( 202312096 )≈  486342.5 , jd ≈0.9926  , k(m)= 1.2
G(202312098) = 816025 ；inf( 202312098 )≈  810570.8 , jd ≈0.9933  , k(m)= 2
G(202312100) = 544895 ；inf( 202312100 )≈  540380.5 , jd ≈0.9917  , k(m)= 1.33333

计算式：
inf( 202312090 ) = 1/(1+ .1345 )*( 202312090 /2 -2)*p(m) ≈ 548322
inf( 202312092 ) = 1/(1+ .1345 )*( 202312092 /2 -2)*p(m) ≈ 810570.8
inf( 202312094 ) = 1/(1+ .1345 )*( 202312094 /2 -2)*p(m) ≈ 424584.7
inf( 202312096 ) = 1/(1+ .1345 )*( 202312096 /2 -2)*p(m) ≈ 486342.5
inf( 202312098 ) = 1/(1+ .1345 )*( 202312098 /2 -2)*p(m) ≈ 810570.8
inf( 202312100 ) = 1/(1+ .1345 )*( 202312100 /2 -2)*p(m) ≈ 540380.5

愚工688 · 发表于 2023-12-10 20:43

重生888@ 发表于 2023-12-9 08:11
能把“不同余”的必然性推导出来，才有前途！计算数据再多，也不能起决定性作用。

任意偶数2A必然能够写成2A=(A-x)+(A+x),决定两个数是否成素数的因素唯有变量x，而变量x的取值区域为自然数小区域【0，A-3】。

自然数中数在除以任意一个素数的余数呈现周期性变化：
除以2时的余数变化：0、1、0、1、0、1、…；
除以3时的余数变化：0、1、2、0、1、2、…；
除以5时的余数变化：0、1、2、3、4、0、1、2、3、4、…；
……
除以r时的余数变化：0、1、2、…、r-2、r-1、0、…；

由给定偶数2A确定了A除以≤√(M-2)的所有素数的余数：j2、j3、j5、j7、…jr；

而对应了变量x的余数条件为与A的余数不构成同余关系，即
除以2，余数不等于j2；
除以3，余数不等于j3与（3-j3）；
除以5，余数不等于j5与（5-j5）；
除以7，余数不等于j7与（7-j7）；
……
在变量除以√(2A)内的每个素数的周期性变化的余数中，排除了与A的余数构成同余关系的余数后，必然有筛余的余数。
这是周期性变化的余数的必然规律。
不与A同余的数依据各组合的不同余数，我们可以用中国余数定理求出具体的值，其中处于【0，A-3】范围的变量x，则与A组成偶数2A的哥德巴赫猜想“1+1”的确切素数对：2A=(A-x)+(A+x) 。

重生888@ · 发表于 2023-12-11 07:44

愚工688 发表于 2023-12-10 12:43
任意偶数2A必然能够写成2A=(A-x)+(A+x),决定两个数是否成素数的因素唯有变量x，而变量x的取值区域为自然 ...

愚工先生，您好！我向来崇拜您的理论的，就是对“必然有”说法，信心不足。谢谢！

重生888@ · 发表于 2023-12-11 16:56

愚工688 发表于 2023-12-10 12:43
任意偶数2A必然能够写成2A=(A-x)+(A+x),决定两个数是否成素数的因素唯有变量x，而变量x的取值区域为自然 ...

愚工先生，您好！我向来崇拜您的理论的，就是对“必然有”说法，信心不足。谢谢！

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哥德巴赫猜想的“1+1”的必然途径——变量与偶数半值不构成同余关系

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