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计算式如下,可以看到 μ值取的是μ=0.15649 ;这是对素对数量连乘积式的相对误差的修正,修正的目的是减小相对误差值,而不是趋于0.
我不知道你说的 μ值的含义是什么?
Sp( 40401660000 *) = 1/(1+ .15649 )*( 40401660000 /2 -2)*p(m) ≈ 141796609.3 , k(m)= 2.909147
Sp( 40401660002 *) = 1/(1+ .15649 )*( 40401660002 /2 -2)*p(m) ≈ 57389476.5 , k(m)= 1.177422
Sp( 40401660004 *) = 1/(1+ .15649 )*( 40401660004 /2 -2)*p(m) ≈ 49910557.5 , k(m)= 1.023982
Sp( 40401660006 *) = 1/(1+ .15649 )*( 40401660006 /2 -2)*p(m) ≈ 97483286.8 , k(m)= 2
Sp( 40401660008 *) = 1/(1+ .15649 )*( 40401660008 /2 -2)*p(m) ≈ 48762752.8 , k(m)= 1.000433
Sp( 40401660010 *) = 1/(1+ .15649 )*( 40401660010 /2 -2)*p(m) ≈ 67395852.6 , k(m)= 1.382716
Sp( 40401660012 *) = 1/(1+ .15649 )*( 40401660012 /2 -2)*p(m) ≈ 125000424.5 , k(m)= 2.564551
Sp( 40401660014 *) = 1/(1+ .15649 )*( 40401660014 /2 -2)*p(m) ≈ 48751774.7 , k(m)= 1.000208
Sp( 40401660016 *) = 1/(1+ .15649 )*( 40401660016 /2 -2)*p(m) ≈ 49784395 , k(m)= 1.021393
Sp( 40401660018 *) = 1/(1+ .15649 )*( 40401660018 /2 -2)*p(m) ≈ 98309644.7 , k(m)= 2.016954
G(40401660000) = 141832022; jdz =sp(m)/s(m) ≈ 0.999750;
G(40401660002) = 57409341; jdz =sp(m)/s(m) ≈ 0.999654;
G(40401660004) = 49916594; jdz =sp(m)/s(m) ≈ 0.999879;
G(40401660006) = 97512949; jdz =sp(m)/s(m) ≈ 0.999696;
G(40401660008) = 48773320; jdz =sp(m)/s(m) ≈ 0.999783;
G(40401660010) = 67409068; jdz =sp(m)/s(m) ≈ 0.999804;
G(40401660012) = 125023806; jdz =sp(m)/s(m) ≈ 0.999813;
G(40401660014) = 48760534; jdz =sp(m)/s(m) ≈ 0.999820;
G(40401660016) = 49802115; jdz =sp(m)/s(m) ≈ 0.999644;
G(40401660018) = 98324976; jdz =sp(m)/s(m) ≈ 0.999844;
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