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发表于 2005-10-21 20:13 | 显示全部楼层 |阅读模式
若数5经过第一次增长变成数6,再增长一次变成数9,那么在这两个变化过程中,平均增长率是多少?
解法一:设平均增长率为X,有:
    5(1+X)^2=9,则 X≈0.34
解法二:设平均增长率为X,有:
    5+5(1+X)+5(1+X)^2=5+6+9
到底哪一个对呢?
(注“^2”为2次方)[DISABLELBCODE]
发表于 2005-10-23 13:30 | 显示全部楼层

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第一个吧.
发表于 2005-10-23 13:33 | 显示全部楼层

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好象不对,应该是(6/5+9/6)/2
发表于 2005-11-3 18:21 | 显示全部楼层

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0.2+0.5=0.7   
0.7/2=
发表于 2005-11-3 22:02 | 显示全部楼层

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还是很难啊,麻烦`!
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发表于 2005-11-3 22:16 | 显示全部楼层

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第一个是正确的
发表于 2010-5-28 08:01 | 显示全部楼层

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网络数学家--------俞根强--------的看家本领:
鉴定评估,卖卖烧饼,理值气壮闹蠢货,,,,
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