请问10^200的（1+1）双记法表法数下限值是多少？

cuikun-186

答：根据崔坤给出的证明r2(N)≥[N/(lnN)^2],则：
r2(10^200)≥[10^200/(ln10^200)^2]
=471,529,242,529,034,750,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000

cuikun-186

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