|
本帖最后由 朱明君 于 2024-1-24 14:10 编辑
(第1题)
\(设\ x^a+y^b=z^c{,}\ 其中\ x{,}y{,}z{,}a{,}b{,}c{,}n为正整数,\)
\(则\left( xz^{nb}\right)^a+\left( yz^{na}\right)^b=z^{nab+c}\)
(第2题)
\(设\ x^a+y^b=z^c{,}\ 其中\ x{,}y{,}z{,}a{,}b{,}c{,}n{,}为正整数,\)
\(若a是nb的倍数,则\left( xz\right)^a+\left( yz^n\right)^b=z^{a+c}\)
(第3题)
\(设\ x^n+y^{n+1}=z^n,其中\ x{,}y{,}z{,}n{,}K为正整数,\)
\(且2^n-1=x=y{,}\ \ 2\left( 2^n-1\right)=z{,}\)
\(则\left( 2^n-1\right)^n+\left( 2^n-1\right)^{n+1}=\left( 2\left( 2^n-1\right)\right)^n\)
\(则\left( xK^{n+1}\right)^n+\left( yK^n\right)^{n+1}=\left( zK^{n+1}\right)^n\)
\(若n=ab,\)
\(则\left( \left( 2^{ab}-1\right)^b\right)^a+\left( 2^{ab\ }-1\right)^{ab+1}=\left( \left( 2\times\left( 2^{ab}-1\right)\right)^b\right)^a,\)
\(则\left( \left( 2^{ab}-1\right)^a\right)^b+\left( 2^{ab}-1\right)^{ab+1}=\left( \left( 2\times\left( 2^{ab}-1\right)\right)^a\right)^b\)
\(则\left( \left( 2^{ab}-1\right)^b\right)^a+\left( 2^{ab}-1\right)^{ab+1}=\left( \left( 2\times\left( 2^{ab}-1\right)\right)^a\right)^b\)
\(则\left( \left( 2^{ab\ \ }-1\right)^a\right)^b+\left( 2^{ab}-1\right)^{ab+1}=\left( \left( 2\times\left( 2^{ab}-1\right)\right)^b\right)^a
\)
(第4题)
\(设n为正整数,\)
\(则\left( 2^n\right)^{n+2}+\left( 2^n\right)^{n+2}=\left( 2\times2^n\right)^{n+1}\)
\(若n+2=ab{,}\ \ n+1=cd{,}\)
\(则\left( \left( 2^n\right)^a\right)^b+\left( \left( 2^n\right)^a\right)^b=\left( \left( 2\times2^n\right)^c\right)^d\)
\(则\left( \left( 2^n\right)^a\right)^b+\left( \left( 2^n\right)^a\right)^b=\left( \left( 2\times2^n\right)^d\right)^c\)
\(则\left( \left( 2^n\right)^b\right)^a+\left( \left( 2^n\right)^b\right)^a=\left( \left( 2\times2^n\right)^c\right)^d\)
\(则\left( \left( 2^n\right)^b\right)^a+\left( \left( 2^n\right)^b\right)^a=\left( \left( 2\times2^n\right)^d\right)^c\)
\(则\left( \left( 2^n\right)^a\right)^b+\left( \left( 2^n\right)^b\right)^a=\left( \left( 2\times2^n\right)^c\right)^d\)
\(则\left( \left( 2^n\right)^a\right)^b+\left( \left( 2^n\right)^b\right)^a=\left( \left( 2\times2^n\right)^d\right)^c\)
(第5题)
\(设x,n为正整数,\)
\(则2^{xn}+2^{xn}=2^{xn+1}\)
\(则\left( 2^n\right)^x+\left( 2^n\right)^x=2^{nx+1}\)
\(则\left( 2^x\right)^n+\left( 2^x\right)^n=2^{nx+1}\)
\(则\left( 2^n\right)^x+\left( 2^x\right)^n=2^{nx+1}\)
\(若mn=a,\)
\(则x^a+y^a=z^{a+1}\)
(第6题)
\(设m,n为奇数,\)
\(则\left( 2^m\right)^n+\left( 2^m\right)^n=\left( 2^{\left( mn+1\right)\div2}\right)^2\)
\(则\left( 2^m\right)^n+\left( 2^n\right)^m=\left( 2^{\left( mn+1\right)\div2}\right)^2\)
\(若mn=a,\)
\(则x^a+y^a=\left( z^{\left( a+1\right)\div2}\right)^2\)
(第7题)
\(设a,b,c,d,n都是奇数,\)其中
\(\left( abcd\cdots n\right)\div a=A,\)
\(\left( abcd\cdots n\right)\div b=B,\)
\(\left( abcd\cdots n\right)\div c=C,\)
\(\left( abcd\cdots n\right)\div n=N,\)
\(且方程左边项数等于x\)
\(则\left( x^A\right)^a+\left( x^B\right)^b+\cdots+\left( x^N\right)^n=\left( x^{\left( \left( ab\cdots n\right)+1\right)\div2}\right)^2\)
(第8题)
\(设x为大于等于2的正整数,n为任意正整数,x又为公式中的前项个数,\)
\(则x^n+x^n+\cdots+x^n=x^{(n+1)}{,}\ \ \ \ \ \ \ 简化公式:x(x^n)=x^{(n+1)}\)
\(x=2{,}代入公式得,2^n+2^n=2^{(n+1),},\)
\(x=3{,}代入公式得,3^n+3^n+3^n=3^{(n+1)},\)
\(x=4{,}代入公式得,4^n+4^n+4^n+4^n=4^{(n+1),},\)
\(\cdots\cdots。\)
(第9题)
\(设n为任意奇数,\)
\(则2^n+2^n=\left\{ 2^{\left( n+1\right)\div2}\right\}^{^2}{,}\)
\(2^1十2^1=2^2,\)
\(2^3十2^3=4^2,\)
\(2^5十2^5=8^2,\)
\(2^7十2^7=16^2,\)
\(......。\)
|
|