方程组求解!

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a^4*b-a*b^4-a+b=0
a^3*b+a*b^3+a^2*b^2-1=0

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a = (sqrt(3*b^8+14*b^4+27)/(2*3^(3/2)*b)+(7*b^4+27)/(54*b))^(1/3)-2*b^2/(9*(sqrt(3*b^8+14*b^4+27)/(2*3^(3/2)*b)+(7*b^4+27)/(54*b))^(1/3))-b/3

b = (sqrt(3*a^8+14*a^4+27)/(2*3^(3/2)*a)+(7*a^4+27)/(54*a))^(1/3)-2*a^2/(9*(sqrt(3*a^8+14*a^4+27)/(2*3^(3/2)*a)+(7*a^4+27)/(54*a))^(1/3))-a/3

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任意一个缺4次项的一元五次方程，均可以分解因式为：

(x^3+b*x+c)*(x^2-((p+q)/6)^(10/3))=0的形式。

【其中：】

b=
(-(q^5+5*p*q^4+10*p^2*q^3+10*p^3*q^2+5*p^4*q+p^5+7776*c)/((q+p)^(2/3)*(2^(10/3)*3^(10/3)*q+2^(10/3)*3^(10/3)*p)))

c= (-(q^5+5*p*q^4+10*p^2*q^3+10*p^3*q^2+(q+p)^(2/3)*(2^(10/3)*3^(10/3)*b*q+2^(10/3)*3^(10/3)*b*p)+5*p^4*q+p^5)/7776)

p=((m+n)^(1/3))

q=((m-n)^(1/3))

m=(-108*c)

n=((m^2-(-12*b)^3)^(1/2))= (((-108*c)^2-(-12*b)^3)^(1/2))

m^2-n^2=-1728*b^3=(-12*b)^3

q=(-2^(4/3)*3^(2/3)*b/(sqrt(3)*sqrt(27*c^2+4*b^3)-9*c)^(1/3))

【当p=0时】
q=(-2^(2/3)*3^(1/3)*(sqrt(3)*sqrt(27*c^2+4*b^3)+9*c)^(1/3))

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表达式 (-(q^5+5*p*q^4+10*p^2*q^3+10*p^3*q^2+(q+p)^(2/3)*(2^(10/3)*3^(10/3)*b*q+2^(10/3)*3^(10/3)*b*p)+5*p^4*q+p^5)/7776)*(-((p+q)/6)^(10/3)) = (q+p)^5*(q^3*(q+p)^(1/3)+3*p*q^2*(q+p)^(1/3)+3*p^2*q*(q+p)^(1/3)+p^3*(q+p)^(1/3)+2^(10/3)*3^(10/3)*b)/(2^(25/3)*3^(25/3))=五次式的常数项

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方程 20*a^3*b^2-12*a*b^4+10*a+5=0

解 1

b = (sqrt(5*a^2-sqrt(5)*sqrt(5*a^6+6*a^2+3*a)/a)/sqrt(6) )

a = (sqrt(-1728*b^12+4320*b^8-3600*b^4+3375*b^2+1000)/(8*15^(3/2)*b^3)-1/(8*b^2))^(1/3)+(6*b^4-5)/(30*b^2*(sqrt(-1728*b^12+4320*b^8-3600*b^4+3375*b^2+1000)/(8*15^(3/2)*b^3)-1/(8*b^2))^(1/3))

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(32*x^2+20*x*y+13*y^2+158)^2 = 169*y^4+520*x*y^3+1232*x^2*y^2+4108*y^2+1280*x^3*y+6320*x*y+1024*x^4+10112*x^2+24964

红树

a=1，求b，c，d

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方程：2(a^2-a+1)=b^2，求a=?，b=?

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方程：2a^2-2a-b^2=-2，求a=?，b=?