|
clc;clear;
x=round(100*rand(5,4)),%x=randi([0 100],5,4);
[n,m]=size(x);
x11=sum(x,2)/m;
[minrow1,minrow2]=min(x11);
[maxrow1,maxrow2]=max(x11);
x12=x;
x12([minrow2 maxrow2],: )=x12([maxrow2 minrow2],: )
x2=x'
for i=1:n
[mincolumn1,mincolumn2]=min(x(i,: ));
fprintf('第%d行最小的数为%d,在第%d列\n',i,mincolumn1,mincolumn2);
end |
|