世界近代三大数学难题简洁的直观证明（文本格式2017年网络普及版）

lusishun

别找累了，哥猜想证明完了。

见：最近的，汉斯出版社，理论数学。鲁思顺  倍数含量筛法与恒等式的妙用

沟道效应

“倍数含量筛法与恒等式”这一雏形，与隔海之岸的谱法“iP首奇数分布比率iPcL与对1联分等式”
这个周氏终极定式相比，有天远之别。自喜可以，以宝示售，无法标价，见高山而知仰止吧。下面
继续发附贴
`````(128∈wP-)=(64-2)×9/77`≈7`∈17~19、29~31、41~43、59~61、71~73、
``````````````````````````````````101~103、107~109````````````````````````````````无误差
`````(128∈wP+)=(64-2)×9/77`≈7`∈19+109、31+97、61+67、67+61、97+31、
``````````````````````````````````109+19``````````````````````````````````````````少1对
`````(130∈wP-)=(65-2)×9/77`≈7`∈17~19、29~31、41~43、59~61、71~73、
`````````````````````````````````101~103、107~109`````````````````````````````````无误差
`````(130∈wP+)=(65-2)×9/77*4/3`≈9`∈17+113、23+107、29+101、41+89、47+83、
```````````````````````59+71、71+59、83+47、89+41、101+29、107+23、113+17````````多3对

沟道效应

`````(132∈wP-)=(66-2)×9/77`≈7`∈17~19、29~31、41~43、59~61、71~73、
`````````````````````````````````101~103、107~109`````````````````````````````````无误差
`````(132∈wP+)=(66-2)×9/77*2/1`≈14`∈19+113、23+109、29+103、31+101、43+89、53+79、
```````59+73、61+71、71+61、73+59、79+53、89+43、101+31、103+29、109+23、113+19`多2对
`````(134∈wP-)=(67-2)×9/77`≈7`∈17~19、29~31、41~43、59~61、71~73
``````````````````````````````````101~103、107~109```````````````````````````````无误差
`````(134∈wP+)=(67-2)×9/77`≈7`∈31+103、37+97、43+91、61+73、67+67、
``````````````````````````````````73+61、91+43、97+37、103+31````````````````````多2对

沟道效应

`````(136∈wP-)=(68-2)×9/77`≈7`∈17~19、29~31、41~43、59~61、71~73、
``````````````````````````````````101~103、107~109````````````````````````````````无误差
`````(136∈wP+)=(68-2)×9/77`≈7`∈23+113、29+107、47+89、53+83、83+53、
``````````````````````````````````89+47、107+29、113+23```````````````````````````多1对
`````(138∈wP-)=(69-2)×9/77`≈7`∈17~19、29~31、41~43、59~61、71~73、
``````````````````````````````````101~103、107~109````````````````````````````````无误差
`````(138∈wP+)=(69-2)×9/77*2/1`≈15`∈29+109、31+107、37+101、41+97、59+79、
````````````````````````67+71、71+67、79+59、97+41、101+37、`107+31、109+29``````少3对

沟道效应

4势``(140∈wP-)=(70-2)×9/77`≈7`∈17~19、29~31、41~43、59~61、71~73
区````````````````````````````````101~103`、107~109、137~139``````````````````````多1对
间```(140∈wP+)=(70-2)×9/77*8/5`≈12`∈13+127、31+109、37+107、43+97、61+79、
`````````````````````````67+73、73+67、79+61、97+43、103+37、109+31、127+13``````无误差
`````(142∈wP-)=(71-2)×9/77`≈8`∈17~19、29~31、41~43、59~61、71~73、
``````````````````````````````````101~103、107~109、137~139```````````````````````无误差
`````(142∈wP+)=(71-2)×9/77`≈8`∈29+113、41+101、53+89、59+83、71+71、
``````````````````````````````````83+59、89+53、101+41、113+29````````````````````多1对

沟道效应

`````(144∈wP-)=(72-2)×9/77`≈8`∈17~19、29~31、41~43、59~61、71~73、
``````````````````````````````````101~103、107~109、137~139```````````````````````无误差
`````(144∈wP+)=(72-2)×9/77*2`≈16`∈13+131、17+127、31+113、37+107、41+103、`43+101、
``````47+97、71+73、73+71、97+47、101+43、103+41、107+37、113+31、127+17、131+13`无误差
`````(146∈wP-)=(73-2)×9/77`≈8`∈17~19、29~31、41~43、59~61、71~73、
``````````````````````````````````101~103、107~109、137~139```````````````````````无误差
`````(146∈wP+)=(73-2)×9/77`≈8`∈19+127、37+109、43+103、67+79、73+73、
```````````````````````````````````79+67、103+43、109+37、127+19``````````````````多1对

沟道效应

`````(148∈wP-)=(74-2)×9/77`≈8`∈17~19、29~31、41~43、59~61、71~73、
```````````````````````````````````101~103、107~109、137~139``````````````````````无误差
`````(148∈wP+)=(74-2)×9/77`≈8`∈17+131、41+107、47+101、59+89、89+59、
``````````````````````````````````101+47、107+41、131+17``````````````````````````无误差
`````(150∈wP-)=(75-2)×9/77`≈8`∈17~19、29~31、41~43、59~61、71~73
``````````````````````````````````101~103、107~109、137~139```````````````````````无误差
`````(150∈wP+)=(75-2)×9/77*8/3`≈22`∈13+137、19+131、23+127、37+113、41+109、
``````````43+107、47+103、53+97、61+89、67+83、71+79、79+71、83+67、89+61、97+53、
``````````103+47、107+43、109+41、113+37、127+23、131+19、137+13``````````````````无误差

lusishun

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您将看到，哥德巴赫猜想与孪生素数猜想的证明。

沟道效应

还是22楼的回复——
“倍数含量筛法与恒等式”这一雏形，与隔海之岸的谱法“iP首奇数分布比率iPcL与对1联分等式”
这个周氏终极定式相比，有天远之别。自喜可以，以宝示售，无法标价，见高山而知仰止吧。下面
继续发附贴

lusishun

沟道效应 发表于 2017-8-5 05:13
还是22楼的回复——
“倍数含量筛法与恒等式”这一雏形，与隔海之岸的谱法“iP首奇数分布比率iPcL与对1联 ...

不是雏形，是彻底完成证明，同时完成两个猜想的证明